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denis-greek [22]
3 years ago
11

What is the ordered pair ?

Mathematics
1 answer:
stepan [7]3 years ago
4 0
It either second or last one :) hope this info get u to the answer
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What is the converse of ​r->(~q v p)
alexira [117]

Answer:

 r =>  (\neg q \ \lor p)  \ \equiv  \  q \ \land \ \neg p => \neg r

Step-by-step explanation:

In general, remember that the converse of    a => b       is     \neg b  =>   \neg a , therefore in this case  a = r   \ \ ,  b = \neg q \ \lor p

so   r =>  (\neg q \ \lor p)  \ \equiv  \  q \ \land \ \neg p => \neg r

   

8 0
3 years ago
Find the equation of the line.<br> Use exact numbers.
luda_lava [24]

Answer:

y = -2x + 5

Step-by-step explanation:

Looking at the line, every time it moves one unit to the right, it goes down two units. Therefore, the slope is -2. Since the y-intercept is 5, the equation of this line is y = -2x+5.

I hope this helped!

<u><em>Please mark as Brainliest!</em></u>

4 0
2 years ago
Find the length of a rectangle with a perimeter of 76 inches and width of 16 inches.
levacccp [35]

Answer:

22 inches

Step-by-step explanation:

Width (16) x 2 = 32

72 (perimeter) - 32 (width x 2) = 44 inches

44 divided by 2 is 22, which is the length.

3 0
2 years ago
Read 2 more answers
In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. Of the students who have a dog as a pet also have cat as a pet.
Travka [436]

Answer:

This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:

"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"

Where X must be a positive number smaller than one, now we can solve it:

we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:

N = 45*(4/5) = 36

And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:

M = 36*X

now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")

M = 36*(1/2) = 18

So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.

5 0
3 years ago
Read 2 more answers
What is the area of the kite?
finlep [7]

Answer:

Step-by-step explanation:

area of kite=product of diagonals ÷2=(30×4)÷2=120/2=60 ft²

3 0
3 years ago
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