Answer: length when perimeter is 78 units: a=26 ,b=13
Length when perimeter is 156 units:
a=26 , b=52
Step-by-step explanation: Given one side =26 , the other is twice as long
Perimeter of a parallelogram =2(a+b)
Using perimeter=78= 2(26+b)
78=52+2b
78-52=2b
26=2b
b=26/2
b=13
When perimeter is 78 units a=26,b=13
Using perimeter =156 units
156=2(26+b)
156=52+2b
156-52=2b
104=2b
b=104/2
b=52
The length of the shortest side of the hexagon is; 41.833 inches
<h3>How to find the perimeter of a Polygon?</h3>
Let the length of the shortest side of the hexagon be x. Now, a hexagon has six sides and if the next side is 10 inches longer than the previous side, then the length of the six sides are;
x, x + 10, x + 20, x + 30, x + 40, x + 50
Perimeter is given as 401 inches. Thus;
x + x + 10 + x + 20 + x + 30 + x + 40 + x + 50 = 401
6x + 150 = 401
6x = 401 - 150
6x = 251
x = 251/6
x = 41.833 inches
Read more about Polygon Perimeter at; brainly.com/question/14490532
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These array of numbers shown above are called matrices. These are rectangular arrays of number that are arranged in columns and rows. It is mostly useful in solving a system of linear equations. For example, you have these equations
x+3y=5
2x+y=1
x+y=10
In matrix form that would be
![\left[\begin{array}{ccc}1&3&5\\2&1&1\\1&1&10\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%265%5C%5C2%261%261%5C%5C1%261%2610%5Cend%7Barray%7D%5Cright%5D%20)
where the first column are the coefficients of x, the second column the coefficients of y and the third column is the constants, When you multiple matrices, just multiply the same number on the same column number and the same row number. For this problem, the solution is