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iren [92.7K]
3 years ago
7

after 3 new students joined, the class had 26 students. which equations can be used to find n, the number of students in class b

efore the 3 new students joined?
Mathematics
1 answer:
Scilla [17]3 years ago
7 0

Answer:

23 were there

Step-by-step explanation:

26 - 3 = 25

helped

A: 3n =26

B: n - 3 =26

C: n + 3 =26

D n/3 =26

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Louann and Carla received equal scores on a test made up of multiple choice questions and an essay. Louann got 14 multiple choic
Gnoma [55]
Louann= 14x+24
Carla= 16x+14
 So basically this is just like solving equations. The way I did this was just put random numbers for x and then solve it.
First attempt: 
14(7)+24=16(7)+14
98+24=112+14
122=126
 Okay the first one didn't work so I use 6 for x. 
Second attempt: 
14(6)+24=16(6)+14
84+24=96+14
108=110

So 6 didn't work and you already should know that the answers should be between 1 and 5. 

So now I going to do 5 for x
Third attempt:
14(5)+24=16(5)+14
70+24=80=14
94=94
 
And so the answer is 5! :D The multiply choice questions were worth 5 points and Louann and Carla had 94 for their scores! I hope this help you out and clear for you! :D
7 0
3 years ago
Read 2 more answers
You are attempting to estimate the number of protester marching through the city
Alenkinab [10]

9514 1404 393

Answer:

  1000

Step-by-step explanation:

If the number of protesters per minute remains a constant, then you could write the proportion ...

  p/12 = 177/2.1

Multiplying by 12 gives ...

  p = 12(177/2.1) ≈ 1011.4

Here, minutes are given to 2 significant figures, and the initial count is given to 3 significant figures. The best you can hope for is that your estimate is good to 3 significant figures:

 1010 protesters

It is probably sufficient to report the number to 2 significant figures*:

  1000 protesters

_____

* Unfortunately, with a number like 1000, the only way you can tell it has 2 significant figures is to report it as 1.0×10³ or 10. hundreds. The trailing zeros are usually not considered significant.

3 0
3 years ago
What happens to the value of the expression 150-j150−j150, minus, j as jjj decreases?
nikklg [1K]

Answer:

The value of the expression increases as j decreases

Step-by-step explanation:

Let f(j) = 150 - j150 - j150

f(j) = 150 - j300

As j decreases, the value of j300 decreases (i.e the farther j300 is from 150). Due to the wider gap between 150 and j300, the value of f(j) increases.

For example:

When j = 1, f(j) = 150 - (300*1) = -150

When j = 0.5, f(j) = 150 - (300*0.5) = 0

When j = 0. f(j) = 150 - (300*0) = 150

It is obvious from the analogy above that the expression 150-j150−j150 increases as j decreases

4 0
3 years ago
Evaluate 3^2 + (5 − 2) ⋅ 4 − 6 over 3.<br> 19<br> 16<br> 46<br> 24
Ludmilka [50]
3^2 +(5-2)* 4-6/3
Parenthesis, Exponents, Multiplication/Division, Addition/Subtraction
3^2+3*4- 6/3
9+3*4- 6/3
9+12- 6/3
9+12-2
9+10
19
So your answer is 19.
8 0
3 years ago
What is the value of the function at x = 3?<br> Enter your answer in the box.
prohojiy [21]

Answer:

  y = 4

Step-by-step explanation:

The graph passes through the point (3, 4), which means that the value of the function is 4 when x=3.

8 0
3 years ago
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