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Vsevolod [243]
2 years ago
8

What is the volume of a cube with length 7 cm? V = lwh cm3

Mathematics
2 answers:
bonufazy [111]2 years ago
5 0
343 Due to the fact that it is all the same length it will just multiply to 343 7*7*7=<span>343</span>
Zanzabum2 years ago
4 0
A cube has all lengths the same so 7 *7*7 = 343
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Use the zeros of the following quadratic to find the x-value of the vertex.
frez [133]
(x-1)^2 is the factored version, so vertex is at 0, which is 1, so, A
6 0
3 years ago
2/3y + 15 = 9 <br> What are the steps for this question
xenn [34]

Answer:

see below

Step-by-step explanation:

2/3y + 15 = 9

Subtract 15 from each side

2/3y + 15-15 = 9-15

2/3y = -6

Multiply each side by 3/2 to isolate y

3/2 * 2/3y = -6 *3/2

y = -9

4 0
2 years ago
Read 2 more answers
Need help! Will mark u brainliest for the right answer!
kirill115 [55]

To find the perimeter of this blue figure, add together the shown lengths of the six sides.  

The three measurements on the top have the LCD 4, so we combine 14 3/4, 4 2/4 and 8 2/4.  The sum is 26 7/4, or 27 3/4, or 27.75.

The three measurements on the bottom share the LCD 5, so we can immediately combine them, obtaining 32 8/5, or 33 3/5, or 33.60.

Combining 27.75 and 33.60 results in 61.35, or 61 35/100, or 61 7/20.

The perimeter of the given figure is 61 7/20.

3 0
3 years ago
Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x' (t) is its velocity, and x'
vodka [1.7K]

Answer:

a) v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

b)  0

c) a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

Step-by-step explanation:

For this case we have defined the following function for the position of the particle:

x(t) = t^3 -6t^2 +9t -5 , 0\leq t\leq 10

Part a

From definition we know that the velocity is the first derivate of the position respect to time and the accelerations is the second derivate of the position respect the time so we have this:

v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

Part b

For this case we need to analyze the velocity function and where is increasing. The velocity function is given by:

v(t) = 3t^2 -12t +9

We can factorize this function as v(t)= 3 (t^2- 4t +3)=3(t-3)(t-1)

So from this we can see that we have two values where the function is equal to 0, t=3 and t=1, since our original interval is 0\leq t\leq 10 we need to analyze the following intervals:

0< t

For this case if we select two values let's say 0.25 and 0.5 we see that

v(0.25) =6.1875, v(0.5)=3.75

And we see that for a=0.5 >0.25=b we have that f(b)>f(a) so then the function is decreasing on this case.  

1

We have a minimum at t=2 since at this value w ehave the vertex of the parabola :

v_x =-\frac{b}{2a}= -\frac{-12}{2*3}= -2

And at t=-2 v(2) = -3 that represent the minimum for this function, we see that if we select two values let's say 1.5 and 1.75

v(1.75) =-2.8125< -2.25= v(1.5) so then the function sis decreasing on the interval 1<t<2

2

We see that the function would be increasing.

3

For this interval we will see that for any two points a,b with a>b we have f(a)>f(b) for example let's say a=3 and b =4

f(a=3) =0 , f(b=4) =9 , f(b)>f(a)

The particle is moving to the right then the velocity is positive so then the answer for this case is: 0

Part c

a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

5 0
3 years ago
What percent of 64 is 48?
melisa1 [442]
75% 
48/64=.75 thus 75%
8 0
3 years ago
Read 2 more answers
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