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viva [34]
2 years ago
11

A class has 25 students - 15 girls and 4 boys. 5 girls and 4 boys are wearing blue. a student is picked at random. what is the p

robability that the studnet is either a boy or girl who is not wearing blue?
Mathematics
1 answer:
Neko [114]2 years ago
4 0
Out of 25 students 9 of them are wearing blue. The probability of a student who is not wearing blue is 16/25.
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8-3(x - 5) + 2x + 3 how do I solve this ​
schepotkina [342]

Answer:

The answer is -x+26.

Step-by-step explanation:

First you distribute the -3 into the parthensis and you get -3x+15. You write the whole expression again plus the -3x+15 you got from the distributing part so 8-3x+15+2x+3. You combine the like terms so the x with the x and the numbers with the numbers. From there you get the answer of -x+26. I hope this helps you! If you need more clarification or more help please type it in the comments below. Thanks!

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2 years ago
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For which acute angles is the following statement true? The complement of the angle is smaller in measure than either of the two
Hitman42 [59]

Let the acute angle be 2x.

Its complement is 90 - 2x.

It is given that this complementary angle is less than each of the bisected angle.

Therefore, 90 - 2x < x

90 < 3x

or, x > 30.

2x > 60

Therefore, the statement is true for all angles that are greater than 60 degrees.

7 0
3 years ago
What type of slop..<br> Undefined<br> Positive slope <br> Zero slope <br> Negative slope
BartSMP [9]

Answer:

zero slope

Step-by-step explanation:

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2 years ago
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Lori creates the following design for a T-shirt.
kakasveta [241]

<u>Solution-</u>

From the figure,

AE = 2.4

EB = 2.8

BC = 11.7


Area of rectangle 1 = 8.68 sq.in

\Rightarrow FH \times HI=8.68

\Rightarrow EB \times HI=8.68  (∵ sides of the rectangle 2)

\Rightarrow 2.8 \times HI=8.68

\Rightarrow HI=3.1


Area of Triangle 1 = 6.48 sq.in

\Rightarrow \frac{1}{2}\times AE \times EG= 6.48

\Rightarrow \frac{1}{2}\times AE \times (EF+FG)= 6.48

\Rightarrow \frac{1}{2}\times AE \times (EF+HI)= 6.48  (∵ sides of the rectangle 1)

\Rightarrow EF+3.1= 5.4

\Rightarrow EF=2.3

\Rightarrow BH=2.3  (∵ sides of the rectangle 2)


BC = BH+HI+IC

\Rightarrow 11.7= 2.3+3.1+IC

\Rightarrow IC=6.3


The area of Rectangle 2,

=EB\times BH =2.8\times 2.3=6.44\ sq.in


The area of Triangle 2,

\frac{1}{2}\times GI \times IC=\frac{1}{2}\times EB \times IC=\frac{1}{2}\times 2.8 \times 6.3=8.82\ sq.in


The area of the whole figure = Area of Triangle 1 + Area of rectangle 1 + Area of Triangle 2 + Area of rectangle 2

= 6.48+8.68+8.82+6.44=30.42 sq.in


6 0
3 years ago
7^8 x 7^3 x 7^4 divided by 7^9 x 7^5 ASAP answer please and thankyou
sergeinik [125]

Answer:

\huge\underline\color{purple}{Answer ☘}

7 {}^{8}  \times 7 {}^{3}  \times 7 {}^{4}  \div 7 {}^{9}  \times 7 {}^{5}  \\  =  > 7 {}^{8 + 3 + 4 - 9 + 5 }  \\  =  > 7 {}^{11}

<h3>furthєr... </h3>

<h2>7¹¹ = 1977326743</h2>

<h2>———————————</h2>

\color{pink}\boxed{Additional \: \: Information♡}

properties \: that \: we \: used \: while  \\  solving \: the \: question \: are \: as \: follows -  \\  \\ x {}^{m}  \times x {}^{n}  = x {}^{m + n}  \\  \frac{x {}^{m} }{x  {}^{n} }  = x {}^{m - n}

<h2>———————————</h2>

hσpє hєlpful~

<h2>~вє вrαínlч!</h2>
8 0
2 years ago
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