The equations that express the relationship between the side lengths of the triangles are
<h3>Pythagorean triple</h3>
From the question, we are to write an equation that expresses the relationship between the side lengths of each triangle
From the Pythagorean theorem,
In a right triangle, the square of the longest side (hypotenuse) equals sum of squares of the other two sides
That is,
c² = a² + b²
Where c is the longest side (hypotenuse)
a and b are the other two sides
The equation is
10² = 6² + 8²
- For
The equation is
- For
The equation is
- For
The equation is
- For
The equation is
Hence, the equations that express the relationship between the side lengths of the triangles are
Learn more on Pythagorean triple here: brainly.com/question/3223211
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The triangle has a translation. All corresponding angles remain congruent. Every point changed coordinates. The triangle retains the original size.
A) True
B) False
C) True
D) False
Answer: A, C
Answer:
25 centimeters
Step-by-step explanation:
1 meter is 100 centimeters.
10 ÷ 4 = 25
Answer:
B-30 - 16| = |-461 = 46 units
Step-by-step explanation:
The distance between -30 and 16 is the absolute value of the difference between the points
| -30 -16| = |-46| = 46 units
9514 1404 393
Answer:
- rewrite: 2x^2 +5x +20x +50
- factored: (x +10)(2x +5)
Step-by-step explanation:
I find this approach the most straightforward of the various ways that trinomial factoring is explained or diagramed.
You want two factors of "ac" that have a total of "b". Here, that means you want factors of 2·50 = 100 that have a total of 25. It is helpful to know your times tables.
100 = 1·100 = 2·50 = 4·25 = 5·20 = 10·10
The sums of these factor pairs are 101, 52, 29, 25, and 20. We want the pair with a sum of 25, so that's 5 and 20.
The trinomial can be rewritten using these factors as ...
2x^2 +5x +20x +50
Then it can be factored by grouping consecutive pairs:
(2x^2 +5x) +(20x +50) = x(2x +5) +10(2x +5) = (x +10)(2x +5)
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<em>Additional comment</em>
It doesn't matter which of the factors of the pair you write first. If our rewrite were ...
2x^2 +20x +5x +50
Then the grouping and factoring would be (2x^2 +20x) +(5x +50)
= 2x(x +10) +5(x +10) = (2x +5)(x +10) . . . . . same factoring