The solution of the equation is x= 3 and y = 2
Step-by-step explanation:
Given,
-3x-4y = -17 and
-x-3y = -9
The system of equation can be rewritten as
3x+4y = 17 ------eq 1 and
x+3y = 9 ------ eq 2
To solve for x and y
Multiplying eq 2 by 3 we get,
3x + 9y = 27
or, 3x = 27-9y
Putting this value of x into eq 1 we get,
27-9y +4y = 17
or, -5y = 17-27
or, -5y = -10
or, y = 2
Now put y=2 in eq 2 we get,
x = 9 - 3(2)
= 3
Hence the solution is x = 3 and y = 2
To find the length and width of 3 different rectangles that have an area of 48 square inches, you can use the factor pairs that result in 48.
The reason is that to find the area of a rectangle you multiply two dimensions.
2 in x 12 in
3 in x 8 in
4 in x 6 in
On all these either one could be the length and the other the width.
Answer:
∠PQS= 3(x +5)
Step-by-step explanation:
∠PQR = 5x + 25
∠SQR+∠PQS= 5x+25
∠PQS = ∠PQR-∠SQR
∠PQS= (5x + 25 )-(2x + 10)
∠PQS = 5x+25 -2x-10
∠PQS= 3x +15
∠PQS= 3(x +5)
Answer:
Option 3)............... I guess so
