Answer:
6c + 36 = 6(c+6)
(6*c) + (6*6) = 6(c+6)
2(3c+3) = 6c+6
(6+c)+(6+6) = neither
3c+6+3c = 6c+6
6c+12 = neither
correct me if I am wrong cuz i haven't done this in 2 years
Step-by-step explanation:
going across the top row then the bottom
Answer:
Josh had $500
Karen had $100
Step-by-step explanation:
J = 5K
J - 20 = 6(K - 20)
5K - 20 = 6K - 120
100 = K
J = 500
X = 5, that’s the answer to question 12
Let us take a number x
The four consecutive numbers will be
x+1, x+2, x+3
Thus our equation will be
x + x+1 + x+2 + x+3 = 42
4x + 6 = 42
4x = 36
x= 36/4
x= 9
Thus the four numbers are (substitute)
x=9
x+1=9+1=10
x+2=9+2=11
x+3=9+3=12
9,10,11,12
