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olga_2 [115]
4 years ago
8

Mr. Lee bought rock to landscape around his house. He paid $122.80 for five ton of rock. How much did each ton cost?

Mathematics
2 answers:
ololo11 [35]4 years ago
8 0
He paid 24.56 per ton 
abruzzese [7]4 years ago
3 0
To get your answer you'd do 122.80/5
And that equals 24.56
So your answer would be A.
Hope this helps :)
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A common inhabitant of human intestines is the bacterium Escherichia coli, named after the German pediatrician Theodor Escherich
Bess [88]

Answer:

a). k = 2.0794

b). A_{t}=A_{0}(2^{3t} )

c). 13107200 cells

d). rate of growth after 6 hours = 27255112

e). 4.76 hours

Step-by-step explanation:

From the formula of bacterial population,

A_{t}=A_{0}e^{kt}

Where A_{t} = Bacterial population after time t

A_{0} = Initial population

k = relative growth factor

t = duration or time

a). For A_{t}=2\times 50=100 cells

and A_{0}=50 cells

Time t = 20 minutes = \frac{1}{3} hours

Now we plug in these values in the formula,

100 = 50(e^{\frac{k}{3}})

e^{\frac{k}{3}}=2

By taking natural log on both the sides of the equation,

\frac{k}{3}(lne)=ln(2)

k = 3ln(2) = 2.0794

b). To get the expression we will plug in the value of k in the formula.

A_{t}=A_{0}e^{kt}

Since k = 3ln(2)

A_{t}=A_{0}e^{3t(ln2)}

Let y = e^{3t(ln2)}

By taking natural log on both the sides of the equation,

lny = ln(e^{3t(ln2)} )

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ln(y) = 3t(ln2)

ln(y) = ln(2)^{3t}

y = 2^{3t}

Now our expression will be A_{t}=A_{0}(2^{3t} )

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A_{6}=50(2^{3\times 6} )

A_{6}=50(2^{18})

A_{6}=50\times (262144)=13107200

d). We can get the rate of growth by finding derivative of the expression

\frac{d}{dt}(A_{t})=\frac{d}{dt}[A_{0}(e^{kt}})]

          = A_{0}[ke^{kt}]

Now \frac{d}{dt}(A_{6})=k.A_{6}

                   = 2.0794×13107200

                   = 27255112

e) From the given formula,

A_{t}=A_{0}(2^{3t} )

1000000=50(2^{3t} )

2^{3t}=20000

3t(ln2) = ln(20000)

t = \frac{ln(20000)}{3(ln2)}

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Tanya [424]

Answer:

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Step-by-step explanation:

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Answer:

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