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victus00 [196]
3 years ago
9

What is 36kg in the ratio of 7:2

Mathematics
1 answer:
MrRa [10]3 years ago
4 0

Answer:

28:2

Step-by-step explanation:

7+2=9

36÷9=4

4×7=28

4×2=8

7:2

28:2

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The company June works for pays her 12$ per hour. She works 30 hours per week, and she receives a paycheck every 2 weeks. How do
lawyer [7]

Answer:720

Step-by-step explanation:

6 0
3 years ago
1<br> 4<br> Joey enlarged a 3-inch by 5-inch photograph on a copy machine. He enlarged it four times. The table below<br> shows
lozanna [386]

Answer:

3) 5.4

Step-by-step explanation:

Given two points (x1, f(x1)) and (x2, f(x2)), the average rate of change is computed as follows:

[f(x2) - f(x1)]/[x2 - x1]

From the original photograph to the fourth enlargement, the points are (0, 15) and (4, 36.6). Replacing into the equation we get:

[36.6 - 15]/[4 - 0] = 5.4

4 0
3 years ago
Combine likes terms to create an equivalent expression 1/7 - 3(3/7h -2/7)
Anastasy [175]

\frac{1}{7} -3(\frac{3}{7}h -\frac{2}{7}) = \frac{7-9h}{7}

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

\frac{1}{7} -3(\frac{3}{7}h -\frac{2}{7})

We have to combine the like terms

From given expression,

\frac{1}{7} -3(\frac{3}{7}h -\frac{2}{7})

By distributive property,

The distributive property lets you multiply a sum by multiplying each addend separately and then add the products.

a(b + c) = ab + bc

Therefore,

Solve for brackets using distributive property

\frac{1}{7} - (3 \times \frac{3}{7}h) + (3 \times \frac{2}{7})\\\\\frac{1}{7} - \frac{9h}{7} + \frac{6}{7}

Add 1/7 and 6/7

\frac{1}{7} + \frac{6}{7} -\frac{9h}{7}\\\\\frac{1+6}{7} -\frac{9h}{7}\\\\Simplify\\\\\frac{7}{7}-\frac{9h}{7}\\\\1-\frac{9h}{7}\\\\Simplify\\\\\frac{7-9h}{7}

Thus the equivalent expression is found

5 0
3 years ago
Why does cube root 7 equal 7 to the 1/3 power
UNO [17]

Answer:

Step-by-step explanation:

Here's how you convert:

\sqrt[n]{x^m}=x^{\frac{m}{n}  The little number outside the radical, called the index, serves as the denominator in the rational power, and the power on the x inside the radical serves as the numerator in the rational power on the x.

A couple of examples:

\sqrt[3]{x^4}=x^{\frac{4}{3}

\sqrt[5]{x^7}=x^{\frac{7}{5}

It's that simple. For your problem in particular:

\sqrt[3]{7} is the exact same thing as \sqrt[3]{7^1}=7^{\frac{1}{3}

8 0
3 years ago
Find the center and radius of the circle (x+3)^2+(y-1)^2=81
sasho [114]

The equation of a circle is written as ( x-h)^2 + (y-k)^2 = r^2

h and k is the center point of the circle and r is the radius.

In the given equation (x+3)^2 + (y-1)^2 = 81

h = -3

k = 1

r^2 = 81

Take the square root of both sides:

r = 9

The center is (-3,1) and the radius is 9

5 0
4 years ago
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