Answer:
Step-by-step explanation:
Given
Bisector: QS
Required
Determine PQR
Since PQR is bisected to PQS and RQS, we have that
Substitute expressions for PQS and RQS
Collect Like Terms
Divide both sides by 3
Solving for PQR;
Substitute 2 for x
Who can help me with my math homework I can ask the questions on here the way they are set up?
1 answer:
You might be interested in
1) Area of trapezoid =1/2(base 1 +base 2)* height
<h3>Answer: Choice B) x = 65, y = 10</h3>
====================================================
Work Shown:
The upper pair of angles 60 degrees and (2x-y) degrees are supplementary angles. This is because of the parallel lines. Note how they are same side interior angles. Therefore, (2x-y) and 60 combine to 180 degrees like so
(2x-y)+60 = 180
2x-y = 180-60 ... subtract 60 from both sides
2x-y = 120 ... call this equation 1
-------
Similarly, (2x+y) and 40 also combine to 180
(2x+y) + 40 = 180
2x+y = 180-40 ... subtract 40 from both sides
2x+y = 140 ... call this equation 2
------
Line up equation 1 and equation 2. Then add straight down
That becomes 4x = 260 which solves to x = 65 when you divide both sides by 4.
------
If x = 65, then,
2x-y = 120
2(65)-y = 120
130 - y = 120
-y = 120-130
-y = -10
y = 10
or
2x+y = 140
2(65)+y = 140
130+y = 140
y = 140-130
y = 10
----------
Either way end up with x = 65 and y = 10