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Greeley [361]
3 years ago
9

A cyclist travels 5.8 km in 30 minutes. What is his average speed in km/h?

Mathematics
2 answers:
Sauron [17]3 years ago
4 0

Answer:

11.6km/h

Step-by-step explanation:

multiply 30 min by 2 to get to an hour

multiply 5.8 by 2 to get to km per hour

Sveta_85 [38]3 years ago
3 0

Answer:

average speed was 11.6 Kilometers per hour

Step-by-step explanation:

hope that helped

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Converting a fraction to a percentage<br> 18/25<br> please include steps
slavikrds [6]

Answer:

72%.

Step-by-step explanation:

We multiply the fraction by 100:

= 100 * 18/25

25 divides into 100 giving 4 so we have:

4 * 18

= 72%.

5 0
3 years ago
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Simplify:<br> −z3+5k6−(−z3+10k6)
natta225 [31]

Answer:

The answer to your question is        -5k⁶

Step-by-step explanation:

Polynomial

                                      - z³  + 5k⁶  - (-z³ + 10k⁶)

Use law of signs for the parenthesis

                                     - z³  + 5k⁶ + z³  - 10k⁶

Use associative property for like terms

                                    (-z³ + z³) + (5k⁶ - 10k⁶)

Simplify like terms

                                    (0)  +   (-5k⁶)

Result

                                               -5k⁶

7 0
3 years ago
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AABC is reflected over the x-axis. What will be the coordinates of C' ?
Anuta_ua [19.1K]

Answer:

hvhhjnblnj. hlvb/ljb/u'n

Step-by-step explanation:

4 0
3 years ago
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Kelly is making a rectangular garden that has a width of (2x + 3) and length of (2x - 4)
Serggg [28]
Answer 2x^2 -12

Explanation
3 0
3 years ago
A = ???? 4 −2
irinina [24]

Answer:

1. The matrix A isn't the inverse of matrix B.

2. |B|=12, |A|=12

Step-by-step explanation:

1. We want to know if matrix A is the inverse of matrix B, this means that if you do the product between B and A you have to obtain the identity matrix.

We have:

A=\left[\begin{array}{cc}4&-2\\-1&3\end{array}\right]

and

B=\left[\begin{array}{cc}3&2\\1&4\end{array}\right]

A and B are 2×2 matrices (2 rows and 2 columns), if you multiply them you have to obtain a 2×2 matrix.

Then if A is the inverse of B:

B.A=I

Where,

I=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]

Observation:

If you have two matrices:

A=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\and\\B=\left[\begin{array}{cc}e&f\\g&h\end{array}\right]\\\\\\A.B=\left[\begin{array}{cc}(a.e+b.g)&(a.f+b.h)\\(c.e+d.g)&(c.f+d.h)\end{array}\right]

Now:

B.A=\left[\begin{array}{cc}3&2\\1&4\end{array}\right].\left[\begin{array}{cc}4&-2\\-1&3\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}4.3+(-2).1&4.2+(-2).4\\(-1).3+3.1&(-1).2+3.4\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}12-2&8-8\\-3+3&-2+12\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}10&0\\0&10\end{array}\right]

B.A=\left[\begin{array}{cc}10&0\\0&10\end{array}\right]\neq \left[\begin{array}{cc}1&0\\0&1\end{array}\right]=I\\\\\\B.A\neq I

Then, the matrix A isn't the inverse of matrix B.

2. If you have a matrix A:

A=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]

The determinant of the matrix is:

|A|=ad-bc

Then the determinant of B is:

B=\left[\begin{array}{cc}3&2\\1&4\end{array}\right]

a=3, b=2, c=1, d=4

|B|=3.4-2.1\\|B|=12-2=10

The determinant of A is:

A=\left[\begin{array}{cc}4&-2\\-1&3\end{array}\right]

a=4, b=-2, c=-1, d=3

|A|=4.3-(-2).(-1)\\|B|=12-2=10

6 0
4 years ago
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