Answer:
1.) 9.9
2.) 15.6
Step-by-step explanation:
1.) Consider triangle AEH
AEH is a right angle triangle as ∠AEH = 90°
AH is the hypotenuse of the triangle.
Applying Pythagorean theorem
substituting values as given in the question:
∴ EH≈9.9
2.) Consider triangle CDF
CDF is a right angle triangle as ∠CDF = 90°
CF is the hypotenuse of the triangle.
Applying Pythagorean theorem
substituting values as given in the question:
∴ DF≈15.6
Answer:
x ≤ 2
Step-by-step explanation:
i hope this helps :)
The upper quartile is 9
Lower quartile: 5
Median: 8
Upper quartile: 9
Step One
Solve for y
Cos(A) = adjacent / hypotenuse
Cos(A) = y / 8
y = 8 * cos(A)
y = 8 * cos(73)
y = 8 * 0.2924
y = 2.339
Step Two
Solve for x
Sin(A) = opposite / hypotenuse
Sin(73) = x / 8
x = 8 * sin(73)
x = 8 * 0.9563
x = 7.550
Check
x^2 + y^2 =? 8^2
2.339^2 + 7.55^2 =? 8^2
5.471 + 58.53 =? 64
64.000921 = 64 which is close enough.
6=-3(x+2)
——Distribute -3(x+2)
6=-3x-6
—-Flip the equation
-3x-6=6
—-add 6 on both sides..the 6’s will cancel each other and 6+6=12
-3x=12
—-divide -3 on both sides..the 3’s will cancel each other and 12 divided by -3 = -4
Answer: x = -4
