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RUDIKE [14]
4 years ago
9

Estimate 14.75 divided by 2.85 by using compatible numbers.

Mathematics
1 answer:
otez555 [7]4 years ago
4 0
To be honest the correct answer would be just 5 because of estimation
so it would be 5.1754386 circle the 5 underline the 1 and Badda bing Badda boom because if something is bigger than 5 you round up one if its lower than leave your beautiful number
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Can you help A B C Or D image is here
Phoenix [80]

Answer:

I'm pretty sure the answer is A.

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3 years ago
PLEASE HELP MEEEE! PLEASEEEEEEEE
cupoosta [38]

Answer:

24 cats: 28 dogs

Step-by-step explanation:

28/21 = 1.33

18 x 1.33 = 24

6 0
3 years ago
Agroup of friends were working on a student film with a budget of $500, which they
mina [271]

Answer:

89%

Step-by-step explanation:

500-55=445

445/500=0.89

0.89x100=89

4 0
2 years ago
Read 2 more answers
How many 3/4 ounce spoonfuls of sugar<br> are in a 5 1/2 ounce bowl?<br> show work please
klasskru [66]

Answer: \frac{22}{3}

Step-by-step explanation: Divide

5\frac{1}{2}\div \frac{3}{4}

Step 1: Convert the mixed number to improper fraction

5 \frac{1}{2} =\frac{11}{2}

= \frac{11}{2}\div \frac{3}{4}

Step 2: Reciprocal

\frac{11}{2}\times \frac{4}{3}

Step 3: Divide the common factors

4 \div 2 = 2\\\\=\frac{11}{1}\times \frac{2}{3}

Step 4: Multiply

\frac{11\times \:2}{1\times \:3}\\\\=\frac{22}{3}

5 0
3 years ago
Real Estate One conducted a recent survey of house prices for properties located on the shores of Tawas Bay. Data on 26 recent s
Ivanshal [37]

Answer:

Step-by-step explanation:

Hello!

Given the data for the variables:

Y: Selling price of a house on the shore of Tawas Bay

X₁: Number of bathrooms of a house on the shore of Tawas Bay.

X₂: Square feet of a house on the shore of Tawas Bay.

X₃: Number of bedrooms of a house on the shore of Tawas Bay.

The multiple regression model is Y= α + β₁X₁ + β₂X₂ + β₃X₃ + εi

a. Using software I've entered the raw data and estimated the regression coefficients:

^α= a= -5531.01

Represents the mean selling price of the houses when 0 bathrooms, 0 square feet and 0 bedrooms.

^β₁= b₁= -1386.21

Represents the modification of the mean selling price of the houses when the number of bathrooms increases in one unit and the square feet and number of bedrooms remain unchanged.

^β₂= b₂= 60.28

Represents the modification of the mean selling price of the houses when the square feet increase in one unit and the number of bathrooms and bedrooms remain unchanged.

^ β₃= b₃= 54797.08

Represents the modification of the mean selling price of the houses when the number of bedrooms increase in one unit and the number of bathrooms and square feet of the houses remain unchanged.

^Y= -5531.01 -1386.21X₁ + 60.28X₂ + 54797.08X₃

b)

R²= 0.55

R²Aj= 0.49

The coefficient of determination gives you an idea of how much of the variability of the dependent variable (Y) is due to the explanatory variables. Each time you add another explanatory variable to the regression the coefficient increases regarding of real contribution of the new variable. This could lead to thinking (wrongly) that the new variables are good to explain the dependent variable.  

The adjusted coefficient of determination is a correction made to the raw coefficient of determination to have a more unbiased estimation of the effect the independent variables have over the dependent variable.

⇒ As you can see both coefficient are around 50%, which means that these explanatory variables

c)

The standard error estimate, this is the estimate of the population variance of the errors. In the ANOVA is represented by the Mean Square of the errors (MME)

Se²= MME= 3837640577.01

Se= 61948.6931

d) and f)

For the hypotheses tests for each slope the t- and p-values are:

α: 0.05

β₁: t_{H_0}= \frac{b_1-\beta_1 }{Sb_1} t= -0.06; p-value: 0.9528 ⇒ Do not reject H₀, the test is not significant.

β₂: t_{H_0}= \frac{b_2-\beta_2 }{Sb_2} t= 2.56; p-value: 0.0180 ⇒ Reject H₀, the test is significant.

β₃: t_{H_0}= \frac{b_3-\beta_3 }{Sb_3} t= 2.28; p-value: 0.0326 ⇒ Reject H₀, the test is significant.

e)

H₀: β₁= β₂= β₃

H₁: At least one βi is different from the others ∀ i=1, 2, 3

α: 0.05

F= 9.03

p-value: 0.0004

⇒ Reject H₀, the test is significant.

I hope it helps!

5 0
3 years ago
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