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Tomtit [17]
3 years ago
5

If ABF= (7x + 20), FBC=(2x - 5), and ABC= 159", find the value of x. x =

Mathematics
1 answer:
s2008m [1.1K]3 years ago
3 0

Given :

∠ABF = ( 7x + 20 )°

∠FBC=(2x - 5)°

∠ABC= 159°

To Find :

The value of x .

Solution :

Assuming B the center of a circle .

So , all three given angles must be added to 360° .

(7x+20)+(2x-5)+159=360\\\\9x+15+159=360\\\\x=20.67

Therefore , the value of x is 20.67° .

Hence , this is the required solution .

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Write the equation of a line that is parallel to y = 1/2x - 4 and that passes through the point (9, -6)
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7 0
3 years ago
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Hitman42 [59]

Hey there! I'm happy to help!

The factors are the numbers you multiply to get 47. And they can't be fractions or numbers with fractions. They have to be integers (numbers without fractions).

So far, we see that we can multiply 1 and 47 to get 47. To see if there are any more, we see what numbers 1-10 we can divide by.

We cannot divide by 2 because 47 is odd.

We cannot divide by 3 because it gives us 15.6666...

We can't divide by 4 because 47 is odd.

We can't divide by 5 because 47 does not have a 5 or 0 in the ones place.

We can't divide by 6 because 47 is odd.

We can't divide by 7 because it gives us 6.714285....

We can't divide by 8 because 47 is odd.

We can't divide by 9 because it gives us 5.2222

And we obviously can't divide it by 10.

Therefore, the factors of 47 are 1 and 47. A number whose only factors are 1 and itself is called a prime number.

I hope that this helps! Have a wonderful day! :D

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3 years ago
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