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Tomtit [17]
3 years ago
5

If ABF= (7x + 20), FBC=(2x - 5), and ABC= 159", find the value of x. x =

Mathematics
1 answer:
s2008m [1.1K]3 years ago
3 0

Given :

∠ABF = ( 7x + 20 )°

∠FBC=(2x - 5)°

∠ABC= 159°

To Find :

The value of x .

Solution :

Assuming B the center of a circle .

So , all three given angles must be added to 360° .

(7x+20)+(2x-5)+159=360\\\\9x+15+159=360\\\\x=20.67

Therefore , the value of x is 20.67° .

Hence , this is the required solution .

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Find the circumference and area of the circle. Use 3.14 or 22/7 for π.
Hoochie [10]

Answer:

  • circumference: 62.8 ft
  • area: 314 ft²

Step-by-step explanation:

The circumference is given by the formula ...

  C = πd

Using the given numbers, the circumference is ...

  C = (3.14)(20 ft) = 62.8 ft

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The area is given by the formula ...

  A = πr² . . . . . where radius r is half the diameter

Using the given numbers, the area is ...

  A = 3.14(10 ft)² = 314 ft²

4 0
3 years ago
How many tons is 4000 pounds
Lady_Fox [76]
2 tons is your answer
And explanation is each ton is 2000 pounds
6 0
3 years ago
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Anne has 3 pairs of blue socks. If she randomly selects a pair of socks.what is the probability that it is a blue?
V125BC [204]

Answer:

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Step-by-step explanation:

5 0
3 years ago
If students’ scores were normally distributed and the mean was 200 with a standard deviation of 40, then what is the probability
Sonja [21]

Answer:

  84%

Step-by-step explanation:

The empirical rule tells you that 68% of the standard normal distribution is within 1 standard deviation of the mean. The distribution is symmetrical, so the amount in the lower tail is (1 -68%)/2 = 16%.

Since the number you're interested in, 240, is one standard deviation above the mean (200 +40), the percentage of interest is the sum of the area of the central part of the distribution along with the lower tail:

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4 0
3 years ago
What is the coefficient of the x5y5-term in the binomial expansion of (2x – 3y)10? 10C5(2)5(3)5 10C5(2)5(–3)5 –10C5(2)5(–3)5 10C
butalik [34]

ANSWER

10C_5(2)^{5}( - 3)^5

EXPLANATION

The given binomial expansion is:

{(2x - 3y)}^{10}

Compare this to

{(a + b)}^{n}

we have a=2x , b=-3y and n=10

We want to find the coefficient of the term

{x}^{5}  {y}^{5}

This implies that, r=5.

The terms in the expansion can be obtained using

T_{r+1}=nC_ra^{n-r}b^r

We substitute the given values to obtain;

T_{5+1}=10C_5(2x)^{10-5}(  - 3y)^5

T_{6}=10C_5(2x)^{5}(3y)^5

T_{6}=10C_5(2)^{5}( - 3)^5 {x}^{5}  {y}^{5}

Hence the coefficient is;

10C_5(2)^{5}( - 3)^5

5 0
3 years ago
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