Answer:
4(3n + 2)
Step-by-step explanation:
as we know perimeter of a square is 4 x side
one side is 3n + 2
4 sides = 4(3n +2)
Answer:
XAW = 3(23) = 69 degrees.
WAY = 23 + 88 = 111 degrees.
ZAY = 8(12) - 23 = 73 degrees.
XAZ = 6(12) + 35 = 107 degrees.
Step-by-step explanation:
The answer choice which represents the solution to the inequality as given in the task content is; x>-2 or x≤ 1.
<h3>What is the solution of the give complex inequality?</h3>
On this note, it follows that the inequalities can be solved individually as follows;
-4 < 3x +2
-6 < 3x
x > -2
Also, 3x +2 ≤ 5
3x ≤ 3
x ≤ 1.
Ultimately, the correct answer choice is; Choice C; x>-2 or x≤ 1.
Read more on complex inequality;
brainly.com/question/24761100
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Answer:
The probability that a performance evaluation will include at least one plant outside the United States is 0.836.
Step-by-step explanation:
Total plants = 11
Domestic plants = 7
Outside the US plants = 4
Suppose X is the number of plants outside the US which are selected for the performance evaluation. We need to compute the probability that at least 1 out of the 4 plants selected are outside the United States i.e. P(X≥1). To compute this, we will use the binomial distribution formula:
P(X=x) = ⁿCₓ pˣ qⁿ⁻ˣ
where n = total no. of trials
x = no. of successful trials
p = probability of success
q = probability of failure
Here we have n=4, p=4/11 and q=7/11
P(X≥1) = 1 - P(X<1)
= 1 - P(X=0)
= 1 - ⁴C₀ * (4/11)⁰ * (7/11)⁴⁻⁰
= 1 - 0.16399
P(X≥1) = 0.836
The probability that a performance evaluation will include at least one plant outside the United States is 0.836.
Answer:
<em>Test statistic </em>
<em> </em>
t = <em>1.076</em>
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given Mean of the Population (μ) = 8.0
<em>Mean of the sample (x⁻) = 8.25</em>
Given data
8,9,9,8,8,9,8,7
Given sample size n= 8
Given sample standard deviation(S) = 0.661
<u><em>Step(ii):-</em></u>
<em>Null hypothesis : H: (μ) = 8.0</em>
<em>Alternative Hypothesis :H:(μ) > 8.0</em>
<em>Degrees of freedom = n-1 = 8-1=7</em>
<em>Test statistic </em>
<em> </em><em></em>
<em> </em>
<em></em>
<em> t = 1.076</em>
<em>Critical value </em>
<em> t₍₇,₀.₀₅₎ = 2.3646</em>
<em>The calculated value t = 1.076 < 2.3646 at 0.05 level of significance</em>
<em>Null hypothesis is accepted</em>
<em>Test the hypothesis that the true mean quiz score is 8.0 against the alternative that it is not greater than 8.0</em>
<em></em>
