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V125BC [204]
3 years ago
9

The average mark of candidates in an aptitude test was 128.5 with a standard deviation of

Mathematics
1 answer:
rewona [7]3 years ago
3 0

Answer:

Step-by-step explanation:

Hello!

The variable of interest is

X: mark obtained in an aptitude test by a candidate.

This variable has a mean μ= 128.5 and standard deviation σ= 8.2

You have the data of three scores extracted from the pool of aptitude tests taken.

148, 102, 152

An outlier is an observation that is significantly distant from the rest of the data set. They usually represent experimental errors (such as a measurement) or atypical observations. Some statistical measurements, such as the sample mean, are severely affected by this type of values and their presence tends to cause misleading results on a statistical analysis.  

Using the mean and the standard deviation, an outlier is any value that is three standard deviations away from the mean: μ±3σ

Using the population values you can calculate the limits that classify an observed value as outlier:

μ±3σ

128.5±3*8.2

(103.9; 153.1)

This means that any value below 103.9 and above 153.1 can be considered an outlier.

For this example, there is only one outlier, that this the extracted score 102

I hope this helps!

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miv72 [106K]

Answer:

The appropriate alternative hypothesis is, <em>Hₐ</em>: <em>p</em>₁ - <em>p</em>₂ > 0.

Step-by-step explanation:

In this case it is provided that Triclosan is a compound often added to products such as soaps, lotions, and toothpaste.

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But a scientist wants to test whether the compound actually is associated with higher incidence of staph infection.

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Denote:

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To test this the hypothesis can be defined as follows:

<em>H₀</em>: The proportion of people with a detectable level of triclosan does not have higher rates of carrying the staph bacteria than people without triclosan, i.e. <em>p</em>₁ - <em>p</em>₂ ≤ 0.

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6 0
3 years ago
Factor 6p^2 +15p+9????
Ivanshal [37]
To factor the trinomial, you can use the ac method where you multiply the first and last terms together (6 and 9) and add up to 15.
In this case ac= 54
2 numbers that multiply to 54 and add up to 15 would be 6 and 9 so place these numbers where the 15 would be:
6p^{2} +9p + 6p+9
Then group terms to simplify:
(6p^{2} +9p)(6p+9)&#10;
Simplify any like terms:
3p(2p+3) 3(2p+3)
And group together again:
(3p+3)(2p+3)
You can simplify a 3 out of the first expression one more time to get:
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8 0
3 years ago
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Answer:

36

Step-by-step explanation:

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7 0
1 year ago
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Please solve asap thanks ​
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Answer:

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Step-by-step explanation:

this is the correct answer

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