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cricket20 [7]
3 years ago
12

Find the value of y for the given value of x y = x + 5; 2 = 3

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
8 0
Wait i think you made a spelling error, did you mean x=3?
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Point T is on a line with a slope of -2. Which of these could be the coordinates of
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D.(2,7) both are correct

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Use the recipe to find how much hair conditioner Helena needs to make a half batch and a double batch
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Iron has a density of 7.87 g/cm^3. What is the mass of a block of iron that is 2cm x 10cm x 5cm?
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Write a fraction equivalent of 1/7
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it is the correct answer for the above mentioned questions

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Find an equation of the set of all points equidistant from the points A(−3, 6, 3) and B(4, 1, −1). Describe the set.
valentinak56 [21]

Answer:

See below

Step-by-step explanation:

I will describe this set in R³. Let P=(x,y,z) be a point equidistant to A and B, that is, the distance from P to A is equal to the distance from P to B.

First, using the usual distance formula, the distance from P to A is equal to d(P,A)=\sqrt{(x-(-3))^2+(y-6)^2+(z-3)^2}=\sqrt{(x+3)^2+(y-6)^2+(z-3)^2}

On the other hand, the distance form P to B is equal to d(P,B)=\sqrt{(x-4)^2+(y-1)^2+(z-(-1))^2}=\sqrt{(x-4)^2+(y-1)^2+(z+1)^2}

P is equidistant from A and B if and only if P satisfies the equation d(P,A)=d(P,B), that is,

\sqrt{(x+3)^2+(y-6)^2+(z-3)^2}=\sqrt{(x-4)^2+(y-1)^2+(z+-1)^2}

Take the square in both sides of this equation to get

(x+3)^2+(y-6)^2+(z-3)^2=(x-4)^2+(y-1)^2+(z+1)^2

(x+3)^2-(x-4)^2+(y-6)^2-(y-1)^2+(z-3)^2-(z+1)^2=0

You can simplify using difference of squares and multiplying like this:

(7)(2x-1)+(-5)(2y-7)+(-4)(2z-2)=0

14x-10y-8z+36=0

which is the equation of a plane.

4 0
3 years ago
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