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fredd [130]
2 years ago
10

How do I estimate 542,817

Mathematics
1 answer:
ioda2 years ago
4 0

Answer:

Step-by-step explanation:

Much depends on how accurate an estimate you want.

If "to the nearest hundred" would be acceptable (it's a lot of work),

Round off 542817 to 542820 and 27398 to 2740.  Then you'd want to subtract 2740 from 542820.  (Again, it's a lot of work.)

Otherwise round off to the nearest thousand:  543000 - 27000.

Or go to the nearest ten thousand:  540,000 - 30,000 = 510,000 (estimate)

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Step-by-step explanation:

3 0
3 years ago
Wath is six hundred ninety- two thousand,four
ki77a [65]
692,004 is the answer

3 0
2 years ago
Read 2 more answers
If (a+7,b+3)=(0,7)find a and b​
Lerok [7]
A+7=0
A+7-7=0-7
A=-7

B+3=7
B+3-3=7-3
B=4
3 0
3 years ago
The graph of a logarithmic function is shown below
LenaWriter [7]
This represents the function : y = log₆ (x).
Proof:
Rewrite this logarithmic function into an exponential form:

 y = log₆ (x)  ↔ x = 6^y

On the graph we see 2 major points A(1,0) and B(6,1). Plug them in x=6^y
1 = 6⁰ = 1 (true)

6 = 6¹ True, then this confirm that the graph equation is  y = log₆ (x)
4 0
3 years ago
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Use the identity x3+y3+z3−3xyz=(x+y+z)(x2+y2+z2−xy−yz−zx) to determine the value of the sum of three integers given: the sum of
fenix001 [56]

ffn

x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)

x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-(xy+yz+zx))

the sum of their squares is 110, So x^2+y^2 + z^2= 110

the sum of their cubes is 684, so  x^3+y^3 + z^3= 684

the product of the three integers is 210, so xyz= 210

the sum of any two products (xy+yz+zx) is 107

Now we plug in all the values in the identity

x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-(xy+yz+zx))

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684 - 630 = (x+y+z)(3)

54 = 3(x+y+z)

Divide by 3 on both sides

18 = x+y+z

the value of the sum of three integers is 18

3 0
3 years ago
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