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3 years ago

Write a recursive definition ,write in algebraic notation 891,297,99,33,11,...

Mathematics

1 answer:

Elodia [21]3 years ago

7 0

$a_1=891\\
a_n=\dfrac{a_{n-1}}{3}$

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PLEASE ANSWER ASAP WORTH 100 points get it right please

Trava [24]

Answer:

See below.

Step-by-step explanation:

Part A:

triangle QPR and triangle PSR are similar

Part B:

Triangle QPR is a right triangle with right angle QPR.

Triangle SPR is a right triangle with right angle PSR.

Angle QPR of triangle QPR corresponds to and is congruent to angle PSR of triangle PSR.

Angle R of triangle QSR corresponds to and is congruent to angle R of triangle PSR.

The similar triangles by AA Similarity are

triangle QPR and triangle PSR

Part C:

QR/PR = PR/SR

16/PR = PR/4

PR² = 16 * 4

PR² = 64

PR = 8

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3 years ago

Which system of equations..

charle [14.2K]

The answer is A. h + 3s = 35 and 2h + s = 20

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3 years ago

Olivia printed invitations for a party. If she printed

Yanka [14]

Answer:

$11$

Step-by-step explanation:

<h2><u>Since we are looking for how many Olivia printed each minute, all we have to do is divide the amount of invitations by the amount of minutes.</u></h2>

<u />

# of invitations / # of minutes

<u>Substitute:</u>

286 invitations / 26 minutes

$==> 11$

4 0

3 years ago

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What is 2 plus 2 also what is the square root of 500

disa [49]

2+2=4 and the square root of 500 is 22.360679775

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3 years ago

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What are the solutions of 3x2 + 14x + 16 = 0?

Leya [2.2K]

Answer:

Given the equation: $3x^2+14x+16=0$

The general equation of quadratic formula for $ax^2+bx+c=0$ where a, b and c are constant;

then, the solution for this equation is given by;

$
x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ ......[1]

From the equation, $3x^2+14x+16=0$ we have

a =2, b=14 and c=16

Substitute these values in [1] to solve for x;

$
x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-14\pm\sqrt{(14)^2-4(3)(16)}}{2(3)}$

$x=\frac{-14\pm\sqrt{196-192}}{6} =\frac{-14\pm\sqrt{4}}{6}$

Simplify:

$x=\frac{-14\pm\sqrt{4}}{6} =\frac{-14\pm 2}{6}$

then,

$x=\frac{-14+2}{6} =\frac{-12}{6} =-2$ and

$x=\frac{-14-2}{6} =\frac{-16}{6} =\frac{-8}{3}$

Therefore, the solutions for the given equation is; x =-2 and $x =-\frac{8}{3}$

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3 years ago

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