The value of the quotient will result in a positive integer compared to the original two integers that started off as a negative integer
Do you mean
![3 \sqrt[3]{125}](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B125%7D%20)
or
![\sqrt[3]{125}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%20)
remember that
![\sqrt[n]{x^m}=x^\frac{m}{n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Em%7D%3Dx%5E%5Cfrac%7Bm%7D%7Bn%7D)
resolve the
![\sqrt[3]{125}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D)
part first
![\sqrt[3]{125}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%3D)
![\sqrt[3]{5^3}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5%5E3%7D%3D)



so
![3 \sqrt[3]{125}=3*5=15](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B125%7D%3D3%2A5%3D15%20)
or
![\sqrt[3]{125} =5](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%20%3D5)
not sure which one you mean
I found the choices that should have been included in this problem.
a) (1.5,26)
b) (2.25,30)
c) (5.5,88)
d) (7.25,110)
y = 16x
choice a. y = 16(1.5) = 24
choice b. y = 16(2.25) = 36
choice c. y = 16(5.5) = 88
choice d. y = 16(7.25) = 116
The correct answer is choice c. (5.5, 88)
Answer:
x=(3,1/4)
Step-by-step explanation:
Be sure to use the formula...
- First, move all variables to one side (left) of the equation. You want one side to be equivalent to zero.
-Next, you need to find a, b, and c. This should be...
a=4
b=-13
c=3
- Knowing this, fill in these variable to go along with the formula. I cannot do this for you, as you should try it on your own. But, you should end up with the solution x= (3,1/4).
- Hope this helps! If you need a further explanation or help on any more problems please let me know, as I would be glad to help anytime.
Answer:
1. 20
2. 23
3. 6
Step-by-step explanation:
We have that:
f(x) = 2x
g(x) = x² + 1
f(g(x)) is the composite function of f and g. So
f(g(x)) = f(x²-1) = 2(x²+1) = 2x² + 2
1. f(g(3))
f(g(x)) = 2x² - 2 = 2(3)² + 2 = 18 + 2 = 20
2. f(3)+g(4)
f(3) = 2(3) = 6
g(4) = 4² + 1 = 17
f(3) + g(4) = 6 + 17 = 23
3. f(5) - 2g(1)
f(5) = 2(5) = 10
g(1) = (1)² + 1 = 2
f(5) - 2g(1) = 10 - 2*2 = 10 - 4 = 6