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IgorLugansk [536]
3 years ago
7

Answers to all and how to do

Mathematics
1 answer:
cestrela7 [59]3 years ago
6 0
1) 4-3/2-1                               
m=1
b=2
y=x+2

2)7-10/-1-2
m=1
b=8
y=x+8

3)8-13/1-2
m=5
b=3
y=5x+3

4)1-3/8-4
m=-1/2
b=5
y=-1/2x+5
go here for the rest.
www.wikihow.com/Find-the-Equation-of-a-Line
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\sf{Circumference = 2\times\pi\times~r}

Where r is the radius of the circle.
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Pls explain How do do all of these and say answers
lyudmila [28]

Answer:

QUESTION ONE-

Cross multiply:

5 * 15 = 12 * y

Simplifying

5 * 15 = 12 * y

Multiply 5 * 15

75 = 12 * y

Solving

75 = 12y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-12y' to each side of the equation.

75 + -12y = 12y + -12y

Combine like terms: 12y + -12y = 0

75 + -12y = 0

Add '-75' to each side of the equation.

75 + -75 + -12y = 0 + -75

Combine like terms: 75 + -75 = 0

0 + -12y = 0 + -75

-12y = 0 + -75

Combine like terms: 0 + -75 = -75

-12y = -75

Divide each side by '-12'.

y = 6.25

Simplifying

y = 6.25

QUESTION TWO-

Cross multiply:

8 * w = 20 * 6

Simplifying

8 * w = 20 * 6

Multiply 20 * 6

8w = 120

Solving

8w = 120

Solving for variable 'w'.

Move all terms containing w to the left, all other terms to the right.

Divide each side by '8'.

w = 15

Simplifying

w = 15

QUESTION 3-

Cross multiply:

s + 1 * 8 = 4 * 4

Simplifying

s + 1 * 8 = 4 * 4

Reorder the terms:

1 + s * 8 = 4 * 4

Reorder the terms for easier multiplication:

8 * 1 + s = 4 * 4

1 * 8 + s * 8 = 4 * 4

8 + 8s = 4 * 4

Multiply 4 * 4

8 + 8s = 16

Solving

8 + 8s = 16

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '-8' to each side of the equation.

8 + -8 + 8s = 16 + -8

Combine like terms: 8 + -8 = 0

0 + 8s = 16 + -8

8s = 16 + -8

Combine like terms: 16 + -8 = 8

8s = 8

Divide each side by '8'.

s = 1

Simplifying

s = 1

Step-by-step explanation:

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Read 2 more answers
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Answer:

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Step-by-step explanation:

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A Martian couple has children until they have 2 males (sexes of children are independent). Compute the expected number of childr
Ne4ueva [31]

Answer:

a) 6

b) 4

c) 3

Step-by-step explanation:

Let p be the probability of having a female Martian, and of course, 1-p the probability of having a male Martian.

To compute the expected total number of trials before 2 males are born, imagine an experiment simulating the fact that 2 males are born is performed n times.

Let ak be the number of trials performed until 2 males are born in experiment k. That is,

a1= number of trials performed until 2 males are born in experiment 1

a2= number of trials performed until 2 males are born in experiment 2

and so on.

If a1 + a2 + … + an = N

we would expect Np females.  

Since the experiment was performed n times, there 2n males (recall that the experiment stops when 2 males are born).

So we would expect 2n = N(1-p), or

N/n = 2/(1-p)

But N/n is the average number of trials per experiment, that is, the expectation.

<em>We have then that the expected number of trials before 2 males are born is 2/(1-p) where p is the probability of having a female. </em>

a)

Here we have the probability of having a male is half as likely as females. So

1-p = p/2 hence p=2/3

The expected number of trials would be

2/(1-2/3) = 2/(1/3) =6

This means <em>the couple would have 6 children</em>: 4 females (the first 4 trials) and 2 males (the last 2 trials).

b)

Here the probability of having a female = probability of having a male = 1/2

The expected number of trials would be

2/(1/2) = 4

This means<em> the couple would have 4 children</em>: 2 females (the first 2 trials) and 2 males (the last 2 trials).

c)

Here, 1-p = 2p so p=1/3

The expected number of trials would be

2/(1-1/3) = 2/(2/3) = 6/2 =3

This means<em> the couple would have 3 children</em>: 1 female (the first trial) and 2 males (the last 2 trials).

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3 years ago
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