Answer:
<h3>5 seccs</h3>
Step-by-step explanation:
Given the modeled function of the height expressed as;
h(t)=-16t^2+64t+80
The ball hits the ground when h(t) = 0 (when the height is zero)
Substitute into the function and find t;
0 =-16t^2+64t+80
divide through by -16
0 = t²-4t-5
Factorize;
t²-4t-5 = 0
t²-5t+t-5 = 0
t(t-5)+1(t-5) = 0
(t+1)(t-5) = 0
t + 1 = 0 and t-5 = 0
t = -1 and t = 5
Time can't be negative
Hence it will take the ball 5secs before it hits the ground
But use this calculator called Photomath you can take a picture of the question and get an instant answer
there are 4,500 of 4 digit multiples of 2
We want to find the greatest common factor of two given expressions.
The GCF is 15*a*b.
The two expressions are:
45*a^3*b^2 and 15*a*b
To find the greatest common factor, we can rewrite the first expression to get:
45*a^3*b^2 = (3*15)*(a^2*a)*(b*b)
Now remember that we can perform a multiplication in any order we want, so we can rearrange the factors to write this as:
(3*15)*(a^2*a)*(b*b) = (15*a*b)*(3*a^2*b)
Then we have:
45*a^3*b^2 = (15*a*b)*(3*a^2*b)
So we can see that 15*a*b is a factor of 45*a^3*b^2, then the GCF between 15*a*b and 45*a^3*b^2 is just 15*a*b.
If you want to learn more, you can read:
brainly.com/question/1986258
