To find out the result, we have to divide 365 days by 28 days:
365 / 28 = 13,03571428571429
So we can see it's 13 lunar months with something extra. To find that something extra we can multiply 28 by 13 and then substract the result from 365:
365 - (13 * 28) =
= 365 - 364 =
= 1
So there are 13 lunar months and one day.
Answer:
1150 km/hr
Step-by-step explanation:
Formula for Average Speed is given as = Distance in Kilometers/ Time in Hours
In the question we are given the following parameters.
The length of a planet's orbit around a star = Distance = 17,650,000 km.
Time taken to complete a full orbit = 640 Earth days
Step 1
We need to convert the time in days to hours
1 Earth day = 24 hours
640 Earth days =
We cross multiply
640 Earth days × 24 hours
= 15360 hours.
Step 2
Average Speed = Distance in Kilometers/ Time in Hours
Average Speed = 17,650,000 km. /15360 hours
Average Speed = 1149.0885417 km/hr
Approximately to 3 significant figures=
1150 km/hr
Therefore, the planets average speed in kmh-1 to 3sf is 1150 km/hr
Answer:
p=-6
q=3
Step-by-step explanation:
5p-3q=-39
-2p-3q=3
Multiply the second equation by -1
2p +3q = -3
Add the first equation and the modified second equation
5p-3q=-39
2p +3q = -3
---------------------
7p = -42
Divide by 7
7p/7 = -42/7
p = -6
Now we can find q
2p +3q = -3
2(-6) +3q = -3
-12 +3q = -3
Add 12 to each side
-12+12 +3q = -3+12
3q = 9
Divide by 3
3q/3 = 9/3
q=3
Answer:
Question 2: 58.88
Question 7: 30,000
Question 8: 213.7
Question 12: p(p+6)
Question 16: 16
Question 19: 35
That the best I could do
Hope It help If not then sorry try to help tho