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igor_vitrenko [27]
3 years ago
9

PLEASE HELP

Mathematics
1 answer:
lora16 [44]3 years ago
8 0

Answer:

The angles and lengths should not change at all the image and pre-image should be the same just at a different place on the graph

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What is the value of the function at x=−2?
adell [148]

x = -2

function value at x = -2 is intersection of the x value and graph

which is, 3

Hope it is clear:)

5 0
3 years ago
The height of a cone is two times its base diameter. What is the volume of the cone in terms of its base radius r? V = r2 V = r3
Gnom [1K]
So hmm check the picture below

the radius "r" is half the diameter, meaning, the diameter is 2r long
now, if the height "h" is twice "d" or 2d, then that means h = 2(2r)

thus    \bf \textit{volume of a cone}\\\\
V=\cfrac{\pi r^2 h}{3}\qquad 
\begin{cases}
h=height\\
r=radius\\
------\\
h=2(2r)
\end{cases}\implies V=\cfrac{\pi r^2[2(2r)]}{3}
\\\\\\
V=\cfrac{4\pi r^3}{3}

8 0
3 years ago
Geometry help needed!
salantis [7]

Answer:

AC Midpoint (2,0)-

CB Midpoint (5,-4)

midlength is 5

Step-by-step explanation:

midpoint formula (\frac{x_{1}+x_{2}  }{2} ,\frac{y_{1} +y_{2} }{2})

A(2,4) C(2,-4)

\frac{2+2}{2} =\frac{4}{2}=2\\\frac{4-4}{2}  =\frac{0}{2} =0

(2,0)

C(2,-4) B(8,-4)

\frac{8+2}{2} =\frac{10}{2} =5

\frac{-4-4}{2} =\frac{-8}{2} =-4  midpoint is  (5,-4)

Distance between the 2 midpoints is the midsegment

(2,0) and (5,-4)

d=\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})  ^{2}   }

d=\sqrt{(5-2)^{2} +(-4-0)^{2}  } \\d=\sqrt{3^{2} +(-4^{2})\\ } \\d=\sqrt{x} 9+16\\d=\sqrt{25} \\d=5

3 0
3 years ago
piano lessons cost $30 per lesson. Find ordered pairs that represent the total cost for x number of lessons. Check all that appl
worty [1.4K]
The cost of each Piano Lesson = $30
If there are x lessons, the total cost of lessons can be expressed as 30x.

Since the number of lessons cannot be negative, the value of x can be 0 or greater than 0, where x=0 shows no lesson.

For 1 lesson, x = 1
So the cost will be = 30(1) = $30
In ordered pair we can write it as (1, 30)

If we consider there is an option to attend half portion of a lecture, then for 1 and half lectures, x = 1.5
So, the cost for 1.5 lectures will be = 30(1.5) = $45
In ordered pair we can write it as (1.5, 45)

For 3 lesson, x = 3
The cost of 3 lessons will be = $90
In ordered pair we can write this as (3, 90)

So, from the given options, only following 2 ordered pairs satisfy the given conditions:
1) (1,30)
2) (3, 90)
4 0
3 years ago
0.327 rounded to the nearest hundredths
daser333 [38]
.33 because the 2 needs to round up hecause there is a number greater than 5 after it
8 0
3 years ago
Read 2 more answers
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