Q = 3s - 9/6
q = 3(s - 3)/6
q = s - 3/2
6q + 9 = 3s
6q + 9/3 = s
3(2q + 3)/3 = s
2q + 3 = s
s = 2q + 3
<h2>6.</h2><h3>Given</h3>
<h3>Find</h3>
- The side length of a regular pentagon whose side lengths in inches are represented by these values
<h3>Solution</h3>
Add 27 to get
... 5x = 2x + 21
... 3x = 21 . . . . . . . subtract 2x
... x = 7 . . . . . . . . . divide by 3
Then we can find the expression values to be
... 5x -27 = 2x -6 = 5·7 -27 = 2·7 -6 = 8
The side of the pentagon is 8 inches.
<h2>8.</h2><h3>Given</h3>
- a rectangle's width is 17 inches
- that rectangle's perimeter is 102 inches
<h3>Find</h3>
- the length of the rectangle
<h3>Solution</h3>
Where P, L, and W represent the perimeter, length, and width of a rectangle, respectively, the relation between them is ...
.... P = 2(L+W)
We can divide by 2 and subtract W to find L
... P/2 = L +W
... P/2 -W = L
And we can fill in the given values for perimeter and width ...
... 102/2 -17 = L = 34
The length of the rectangle is 34 inches.
Volume of first pool - V1(t) = 1285 + 32.75t
Volume of 2nd pool - V2(t) = 1600 + 22.25t
Find t when V1 = V2
Equating we get - 1285 + 32.75t = 1600 + 22.25t
Solving for t we get 87.14 minutes
To find the Volume just substitute this value of t in one of the equations
Answer:
Answer is AAAAAAAAAAAA
Step-by-step explanation:
AAAAAAAA the first one