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lara31 [8.8K]
4 years ago
6

3{x-2}>-3 sovle the inequality for x

Mathematics
2 answers:
lianna [129]4 years ago
8 0

Step-by-step explanation:

3x - 6 > -3

3x >-3 +6

3x>3

x > 1

NikAS [45]4 years ago
4 0

Answer:

x > 1

Step-by-step explanation:

Firstly simplify the bracket...,

3(x-2) = 3x - 6

Then substitute the simplified form into your inequality

; 3x-6 > -3....then move (-6) to the right hand side..so that we can have the values with no x variable

; 3x > 6 - 3...then divide both sides by 3

; 3x > 3

; x > 1

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1. Let f(x) = x + 3 and g(x) = 3x + 5. Find f(g(4)) - g(f(4)) 2. Let f(x) = 5x^2 - 5. What is f(f(x))? 3. Let f(g(x)) = 3x + 3 a
ludmilkaskok [199]

Answer:

1. f(g(4)) - g(f(4)) = -6

2. f(f(x)) = 125x^4 - 250x^2 + 120

3. a + b = 0

4. g(4) = -9

Step-by-step explanation:

1.

First we need to find f(4) and g(4):

f(4) = 4 + 3 = 7

g(4) = 3*4 + 5 = 17

Then, we find g(f(4)) = g(7):

g(7) = 3*7 + 5 = 26

And we find f(g(4)) = f(17):

f(17) = 17 + 3 = 20

so f(g(4)) - g(f(4)) = 20 - 26 = -6

2.

To find f(f(x)), we use the value of f(x) for every x in f(x):

f(f(x)) = 5*(f(x))^2 - 5 = 5*(5x^2 - 5)^2 - 5 = 5*(25x^4 - 50x^2 + 25) - 5

f(f(x)) = 125x^4 - 250x^2 + 120

3.

To find f(g(x)), we use the value of g(x) for every x in f(x):

f(g(x)) = g(x) + 6 = ax + b + 6 = 3x + 3

ax + (b+6) = 3x + 3 -> a = 3 and b = -3

a + b = 3 - 3 = 0

4.

If we assume g(x) = ax + b, we have:

g(f(x)) = a*(2x - 3) + b = 2ax - 3a + b = 5 - 4x

2a = -4 -> a = -2

-3a + b = 5

6 + b = 5 -> b = -1

g(x) = -2x - 1

g(4) = -2*4 - 1 = -9

7 0
3 years ago
WILL GIVE BRAINLET !!!<br> 2 1/12 + 4/12 ( show how u her the answer )
spin [16.1K]

Answer:

2 5/12

Step-by-step explanation:

you can combine two fractions if they have the same denominator (bottom number) by adding the numerators (top numbers) and keeping the bottom number the same.

1/12+4/12 is the same as 1+4 you just put the sum over 12:

2 1/12+4/12= 2 5/12

it can also be written as 29/12

8 0
3 years ago
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