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EleoNora [17]
2 years ago
15

You go the grocery store and buy 7 bags of gummy bears and 3 chocolate bars. Your total was $22. Next time you go, you buy 3 bag

s of gummy bears and 1 chocolate bar for a total of $8. What is the cost of each bag of gummy bears?
Mathematics
1 answer:
fomenos2 years ago
5 0

Answer:

D. $24.75

Step-by-step explanation:

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The scores on a test given to all Júniors in a school district are normally distributed with a mean of 74 and a standard deviati
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In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist
shepuryov [24]

Question Continuation

Find the following probabilities. (Round your answers to four decimal places.)

(a) 15 or more will live beyond their 90th birthday

(b) more than 40 will live beyond their 90th birthday

Answer:

a. 0.9948

b. 0.0068

Step-by-step explanation:

Given

Number of graduating students, n = 723

Probability, p = 3.8% = 0.038

q = 1 - p = 1 - 0.038 = 0.962

Calculating the mean

Mean, u = np

u = 723 * 0.038

u = 27.474

Calculating the standard deviation

σ = √npq

σ = √(723 * 0.038 * 0.962)

σ = 5.14101040652516088641079

σ = 5.141 --- Approximated

We'll solve the following using z = (x-u)/σ

a.

x = 14.5 (I.e Atleast 15)

u = 27.474

σ = 5.141

Z = (14.5 - 27.474)/5.141

Z = −2.5236335343318420540750

Z = -2.52

From the binomial distribution table

The corresponding value at z = -2.52 is 0.0052

So, the probability that 15 or more will live beyond their 90th birthday = 1 - 0.0052

= 0.9948

b.

For more than 40

x = 40.5

u = 27.474

σ = 5.141

Z = (40.5 - 27.474)/5.141

Z = 2.53374829799649873565454

Z = 2.53

From the binomial distribution table

The corresponding value at z = 2.53 is 0.9932

So, the probability that more than 40 will live beyond their 90th birthday = 1 - 0.9932

= 0.0068

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3 years ago
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70 * 4.5 = 315

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3 years ago
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Answer:

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Step-by-step explanation:

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