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Serhud [2]
3 years ago
14

A point charge q1 = 3.30nC is located on the x-axis at x= 1.90m , and a second point charge q2= -6.40 nC is on the y-axis at y=

1.15 m.
1-)What is the total electric flux due to these two point charges through a spherical surface centered at the origin and with radius r1= 0.625m ?
Mathematics
1 answer:
Dahasolnce [82]3 years ago
3 0

Answer:

Step-by-step explanation:

charge q1 is placed at x = 1.90 m and the charge q2 is placed at y = 1.15 m

here, the charge enclosed in a sphere is zero as the radius of sphere is 0.625 m which is less than the x = 1.90 m and y = 1.15 m. So by the Gauss's theorem,

\phi =\frac{q}{\epsilon _{0}}

where q is the charge enclosed, as the charge enclosed is zero so the electric flux is zero.

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We have been given that a school flag poll casts a 16 foot shadow on the lawn. A teacher stood at the shadows edge and measure the angle of elevation to the top of the poll at 62°. We are asked to find the height of the tall.

First of all, we will draw a diagram to represent our give scenario as shown in the attachment.

We can see that side length with 16 feet is adjacent side and height of the pole (h) is opposite side to angle of elevation.

We know that tangent relates opposite side of a right triangle to its adjacent side.

\text{tan}=\frac{\text{Opposite}}{\text{Adjacent}}

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h=16\cdot 1.880726465346

h=30.0916234\approx 30.1

Therefore, the poll is approximately 30.1 feet tall.

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