The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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Answer:
A
Step-by-step explanation:
supplementary agles add up to 180 degrees, so when you subtract 162 from 180, you get 18. Hope this helped :D
If you have two statements p and q and

is
true, then

is also true.
In your case, statements are p - "x is odd" and q - "2x is even".
Then

- "x is not odd" and

- "2x is not even."
Hence

sounds as: "If 2x is not even, then x is not odd".
Answer: correct choice is D.
In short, for a vertical parabola, namely one whose independent variable is on the x-axis, usually is x², if the leading term coefficient is negative, the parabola opens downward, and its peak or vertex is at a maximum, check the picture below at the left-hand-side.
and when the leading term coefficient is positive, the parabola opens upwards, with a minimum, check the picture below at the right-hand-side.
Answer: 24°, 48°, 108°
Step-by-step explanation: