Answer: the length of the base is 290ft
The width of the base is 175 ft
Step-by-step explanation:
The base of the building is rectangular in shape.
Let L represent the length of the base of the building.
Let W represent the width of the base of the building.
The length of the base measures 60 ft less than twice the width. This means that
L = 2W - 60 - - - - - - - - -1
The perimeter of a rectangle is expressed as 2(length + width).
The perimeter of this base is 930ft. It means that
2(L + W) = 930
L + W = 930/2 = 465- - - - - - 2
Substituting equation 1 into equation 2 , it becomes
2W - 60 + W = 465
3W = 465 + 60 = 525
W = 525/3 = 175
L = 465 - W = 465 - 175
L = 290
The perimeter of the regular polygon is 70 inches
<h3>How to determine the perimeter of the regular polygon?</h3>
The sides of the regular polygon is given as:
Side = 10 in
The regular polygon has 7 sides
So, the perimeter of the polygon is calculated as:
P = Side lengths * Number of sides
This gives
P = 10 inches * 7
Evaluate
P = 70 inches
Hence, the perimeter of the regular polygon is 70 inches
Read more about perimeter at
brainly.com/question/24571594
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Part I
We have the size of the sheet of cardboard and we'll use the variable "x" to represent the length of the cuts. For any given cut, the available distance is reduced by twice the length of the cut. So we can create the following equations for length, width, and height.
width: w = 12 - 2x
length: l = 18 - 2x
height: h = x
Part II
v = l * w * h
v = (18 - 2x)(12 - 2x)x
v = (216 - 36x - 24x + 4x^2)x
v = (216 - 60x + 4x^2)x
v = 216x - 60x^2 + 4x^3
v = 4x^3 - 60x^2 + 216x
Part III
The length of the cut has to be greater than 0 and less than half the length of the smallest dimension of the cardboard (after all, there has to be something left over after cutting out the corners). So 0 < x < 6
Let's try to figure out an x that gives a volume of 224 in^3. Since this is high school math, it's unlikely that you've been taught how to handle cubic equations, so let's instead look at integer values of x. If we use a value of 1, we get a volume of:
v = 4x^3 - 60x^2 + 216x
v = 4*1^3 - 60*1^2 + 216*1
v = 4*1 - 60*1 + 216
v = 4 - 60 + 216
v = 160
Too small, so let's try 2.
v = 4x^3 - 60x^2 + 216x
v = 4*2^3 - 60*2^2 + 216*2
v = 4*8 - 60*4 + 216*2
v = 32 - 240 + 432
v = 224
And that's the desired volume.
So let's choose a value of x=2.
Reason?
It meets the inequality of 0 < x < 6 and it also gives the desired volume of 224 cubic inches.
Answer:
x =1/12(1-√(97) )
Step-by-step explanation:
