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3 years ago

The relationship between numbers in list X and list Y follows the rule Y = X +2.05 what diagram shows this relationship

Mathematics

1 answer:

dexar [7]3 years ago

6 0

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

y=x+2.05

This is a linear equation ( equation of a line)

To graph the line find the intercepts

The y-intercept is the value of y when the value of x is equal to zero

For x=0

y=0+2.05=2.5

The y-intercept is the point (0,2.05)

The x-intercept is the value of x when the value of y is equal to zero

For y=0

0=x+2.05

x=-2.05

The x-intercept is the point (-2.05,0)

To graph the line plot the intercepts and then join the points

using graphing tool

see the attached figure

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Which pair of functions have the same domain? A. F(x)= sin x and g(x) = tan x B. F(x) = cos x and f(x) = csc x C. G(x) = tan x a

EastWind [94]

Answer:

The correct choice is D

Step-by-step explanation:

The trigonometric functions, $\sin x$ and $\cos x$ are defined for all real numbers.

$\tan x=\frac{\sin x}{\cos (x)}$ , this function is not defined where $\cos x=0$ .

$\cot x=\frac{\cos x}{\sin (x)}$ , this function is not defined where $\sin x=0$ .

$\csc x=\frac{1}{\sin (x)}$ , this function is not defined where $\sin x=0$ .

For option A

The domain of $f(x)=\sin(x)$ is all real numbers.

The domain of g(x) =tanx is $x\ne \frac{(2n+1)\pi}{2}$

For option B

The domain of $f(x)=\cos(x)$ is all real numbers.

The domain of f(x) =csc(x) is $x\ne n\pi$

For option C,

The domain of G(x) =tanx is $x\ne \frac{(2n+1)\pi}{2}$

The domain of f(x) =cot(x) is $x\ne n\pi$

For option D;

The domain of f(x) =cot(x) is $x\ne n\pi$

The domain of f(x) =csc(x) is $x\ne n\pi$

3 0

3 years ago

Read 2 more answers

Describe the given set with a single equation or with a pair of equations. The plane through the point (7 comma 6 comma negative

devlian [24]

Answer:

(a) Along the xy-plane,

7x + 6y = 0

(b) Along the yz-plan,

2y - 3z = 0

7x - 3z = 0

Step-by-step explanation:

To describe the given set.

Given the plane (7, 6, -3),

We have the equation as

7x + 6y - 3z = 0

(a) Along the xy-plane, z = 0, and we have

7x + 6y = 0

(b) Along the yz-plan, x = 0, and we have

6y - 3z = 0

2y - 3z = 0

7x - 3z = 0

8 0

2 years ago

The surface area of this regular pyramid is 1040 cm2. The base is a regular pentagon with side b = 16 cm and slant height l =15

Valentin [98]

Answer:

(a) = 11 cm

Step-by-step explanation:

The formula for finding the surface area of a regular pyramid is B + (1/2*P*l), with B being the area of the base, p being the perimeter of the base, and l being the slant of the pyramid.

The area of a pentagon can be solved using the formula 1/2*a*p, with a being the apothem and p being the perimeter of the pentagon.

B + (1/2*80*15) = 1040
B + 600 = 1040
1040 - 600 = 440 (440 is the area of pentagon)
1/2*a*(16*5) = 440
40*a = 440
440/40 = 11

The apothem is 11 cm. Hope this helps!

6 0

2 years ago

5 | 9 - 5n|-7 = 38 I need helppp.

DerKrebs [107]

Answer:

I got 0 or 18/5

Step-by-step explanation:

8 0

3 years ago

Match each equation with its solution set.

taurus [48]

Answer:

1- The solution of I2x + 5I = 9 is {-7 , 2}

2- The solution of I2x + 7I + 2 = 11 is {-8 , 1}

3- The solution of I5 - xI = 6 is {-1 , 11}

4- The solution of I6x - 8I + 7 = 5 is ∅

5- The solution of Ix + 3I = 12 is {-15 , 9}

6- The solution of Ix - 3I = -12 is ∅

Step-by-step explanation:

* At first lets explain the meaning of IxI = a

- If IxI = a ⇒ then x = a or x = -a

- IxI never give a negative answer, because IxI means the

magnitude of x is always positive

Ex: I-2I is 2

* Now lets find the solution of each equation

1- ∵ I2x + 5I = 9

∴ 2x + 5 = 9 ⇒ subtract 5 from both sides

∴ 2x = 4 ⇒ divide both sides by 2

∴ x = 2

∴ 2x + 5 = -9 ⇒ subtract 5 from both sides

∴ 2x = -14 ⇒ divide both sides by 2

∴ x = -7

* The solution of I2x + 5I = 9 is {-7 , 2}

2- ∵ I2x + 7I + 2 = 11 ⇒ Subtract 2 from both sides

∴ I2x + 7I = 9

∴ 2x + 7 = 9 ⇒ subtract 7 from both sides

∴ 2x = 2 ⇒ divide both sides by 2

∴ x = 1

∴ 2x + 7 = -9 ⇒ subtract 7 from both sides

∴ 2x = -16 ⇒ divide both sides by 2

∴ x = -8

* The solution of I2x + 7I + 2 = 11 is {-8 , 1}

3- ∵ I5 - xI = 6

∴ 5 -x = 6 ⇒ subtract 5 from both sides

∴ -x = 1 ⇒ divide both sides by -1

∴ x = -1

∴ 5 -x = -6 ⇒ subtract 5 from both sides

∴ -x = -11 ⇒ divide both sides by -1

∴ x = 11

* The solution of I5 - xI = 6 is {-1 , 11}

4- ∵ I6x - 8I + 7 = 5 ⇒ Subtract 7 from both sides

∴ I6x - 8I = -2

- I I never give negative answer

* The solution of I6x - 8I + 7 = 5 is ∅

5- ∵ Ix + 3I = 12

∴ x + 3 = 12 ⇒ subtract 3 from both sides

∴ x = 9

∴ x + 3 = -12 ⇒ subtract 3 from both sides

∴ x = -15

* The solution of Ix + 3I = 12 is {-15 , 9}

6- ∵ Ix - 3I = -12

- I I never give negative answer

* The solution of Ix - 3I = -12 is ∅

4 0

3 years ago