Answer:
The probability that at least 1 car arrives during the call is 0.9306
Step-by-step explanation:
Cars arriving according to Poisson process - 80 Cars per hour
If the attendant makes a 2 minute phone call, then effective λ = 80/60 * 2 = 2.66666667 = 2.67 X ≅ Poisson (λ = 2.67)
Now, we find the probability: P(X≥1)
P(X≥1) = 1 - p(x < 1)
P(X≥1) = 1 - p(x=0)
P(X≥1) = 1 - [ (e^-λ) * λ^0] / 0!
P(X≥1) = 1 - e^-2.67
P(X≥1) = 1 - 0.06945
P(X≥1) = 0.93055
P(X≥1) = 0.9306
Thus, the probability that at least 1 car arrives during the call is 0.9306.
Answer:
i think it is Rewrite in Standard Form y=2x+5. y=2x+5 y = 2 x + 5.
Step-by-step explanation:
Step-by-step explanation:
<h2>
<em><u>The following graph shows the ... ... or not to continue the recent lunch special promotion at his restaurant. ... earned, y, from the number of lunch specials ordered per hour, x.</u></em></h2>
Answer:
a b c
plz give branliest
Step-by-step explanation:
Part A:
23 + 13x ≤ 81
Part B:
23 + 13x ≤ 81
<u>-23 </u> <u>-23</u>
13x ≤ 58
<u>/13 </u> <u>/13</u>
x ≤ 4.46
Part C:
This means that you can have 4 cheeseburgers while keeping the fat under 81 grams.
