<h3>9 × 6</h3>
Because the surface area is rectangle and the area of rectangle is length × width
length = 9
width = 6.
so 9×6
Answer:
min = a_1
for i:= 2 to n:
if
< min then min = 
return min
Step-by-step explanation:
We call the algorithm "minimum" and a list of natural numbers 
So lets first set the minimum to 
min = a_1
now we want to check all the other numbers.
We can use a simple for loop, to find the minimum
min = a_1
for i:= 2 to n:
if
< min then min = 
return min
Answer:
The simplification is done below.
Step-by-step explanation:

= 
=
= 
Answer:
-16
Step-by-step explanation:
3^2-7(3)-4