Answer:
I think is it 27 divided by 3 or 3/27
Step-by-step explanation:
Answer:
Move downward by 7 units
Move leftward by 6 units

Step-by-step explanation:
Given
See attachment for grid
Required
The transformation from the current location to the new location
To do this, we pick two corresponding points on the current location and the new location.
We have:
-- Current location
-- New location
First, move A downwards by 7 units.
The rule to this is:

So, we have:


Next, move the above points leftward by 6 units.
The rule to this is:

So, we have:


Answer: see proof below
<u>Step-by-step explanation:</u>
Given: A + B + C = π → C = π - (A + B)
→ sin C = sin(π - (A + B)) cos C = sin(π - (A + B))
→ sin C = sin (A + B) cos C = - cos(A + B)
Use the following Sum to Product Identity:
sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]
cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]
Use the following Double Angle Identity:
sin 2A = 2 sin A · cos A
<u>Proof LHS → RHS</u>
LHS: (sin 2A + sin 2B) + sin 2C




![\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]](https://tex.z-dn.net/?f=%5Ctext%7BFactor%3A%7D%5Cqquad%20%5Cqquad%20%5Cqquad%202%5Csin%20C%5Ccdot%20%5B%5Ccos%20%28A-B%29%2B%5Ccos%20%28A%2BB%29%5D)


LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C 
Answer:
5 and -3
Step-by-step explanation:
cause 2 and 7 are constants
Answer:
x=2
Step-by-step explanation:
-3 = -2x +1
+3 +2x = +2x +3
2x=4
divide them both by 2
x=2