Question

if f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)? a: 6 – 3 – (4 3)2 b: 6 – 3 – (4 – 32) c: 6(3) – 4 32 d:6(3) – 4 – 32

Answer 1

F(x) = 4 - x^2
g(x) = 6x
(g - f)(x) = 6x - (4 - x^2)
(g - f)(3) = 6(3) - (4 - 3^2) = 6(3) - 4 + 3^2

Answer 2

Answer:

Option c is correct

$6(3) - 4 +3^2$

Step-by-step explanation:

Given the functions:

$f(x) = 4-x^2$

$g(x) = 6x$

We have to find $(g-f)(3)$.

$(g-f)(3) = g(3) -f(3)$

Substitute x = 3 in the given functions we have;

$f(3) = 4 -3^2$

$g(3) = 6(3)$

Substitute these we have;

$(g-f)(3) = 6(3) - (4 -3^2)$

⇒$(g-f)(3) = 6(3) - 4 +3^2$

Therefore, the value of $(g-f)(3)$ is, $6(3) - 4 +3^2$