Here we have , A construction crew must build 4 miles of road in one week. On Monday, they build 1/2 mile of road. On Tuesday, they build 1/3 mile of road. We need to find that How many more miles of road are left to build . Let's find out:

On Monday, they build 1/2 mile of road.
On Tuesday, they build 1/3 mile of road.

Let Miles of road left to build is x So,

⇒ $\frac{1}{2} +\frac{1}{3} +x = 4$

⇒ $x = 4 - (\frac{1}{2} +\frac{1}{3})$

⇒ $x = 4 - (\frac{1(3)+1(2)}{6} )$

⇒ $x = 4 - (\frac{5}{6} )$

⇒ $x = (\frac{4(6)-5}{6} )$

⇒ $x = \frac{24-5}{6}$

⇒ $x = \frac{19}{6}$

Therefore, $\frac{19}{6}$ many more miles of road are left to build .

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3 years ago

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F(x) = 8x - 1 Find f(-10) =

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Answer:

-81

Step-by-step explanation:

f(x) = 8x -1

f(-10) = 8(-10) -1

f(-10) = -80-1

f(-10) = -81

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Find vÌ, the orthogonal projection of v onto w. you can't enter vÌ as a variable name in matlab, so call it vbar instead. also c

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Jjjjjjjjjjjjjjjjjjjj

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