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IrinaVladis [17]
3 years ago
12

The sum of two consecutive even integers is 122. what are the integers?​

Mathematics
2 answers:
ioda3 years ago
7 0

Answer:

60 and 62

Step-by-step explanation:

To find the answer we need to set up our problem.

For the two consecutive even integers we can call them x and x+2, as adding 2 to x will give us the next even number.

Then we form our equation:

x+x+2=122

Since we have two x we can combine them into a single term

2x+2=122

We then subtract 2 from both sides

2x=120

Divide by 2

x=60

Find the second number by inserting it into

x+2

60+2=62

Volgvan3 years ago
4 0

Answer:

If the numbers were the same, they'd both be 61

So, try 60 and 62.

x + x+2 = 122

2x = 120

x = 60

Hope that helps!

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Because the number of degrees in a triangle is 180 degrees so x = 180 - (45 + 60) = 75. Now w + 75 = 180 , therfore w = 105 degrees.


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Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).
NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}

Now, differentiate to obtain

\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}

=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}

To obtain the required form, extract a factor in both the numerator and denominator:

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3 0
4 years ago
Can a math god help me out?
Taya2010 [7]

Answer:

f(1)=70

f(n)=f(n-1)+6

Step-by-step explanation:

One is given the following function:

f(n)=64+6n

One is asked to evaluate the function for (f(1)), substitute (1) in place of (n), and simplify to evaluate:

f(1)=64+6(1)

f(1)=64+6

f(1)=70

A recursive formula is another method used to represent the formula of a sequence such that each term is expressed as a function of the last term in the sequence. In this case, one is asked to find the recursive formula of an arithmetic sequence: that is, a sequence of numbers where the difference between any two consecutive terms is constant. The following general formula is used to represent the recursive formula of an arithmetic sequence:

a_n=a_(_n_-_1_)+d

Where (a_n) is the evaluator term (a_(_n_-_1_)) represents the term before the evaluator term, and (d) represents the common difference (the result attained from subtracting two consecutive terms). In this case (and in the case for most arithmetic sequences), the common difference can be found in the standard formula of the function. It is the coefficient of the variable (n) or the input variable. Substitute this into the recursive formula, then rewrite the recursive formula such that it suits the needs of the given problem,

a_n=a_(_n_-_1_)+d

a_n=a_(_n_-_1_)+6

f(n)=f(n-1)+6

3 0
3 years ago
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