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neonofarm [45]
3 years ago
12

Maribel purchased 15 yards of fabric for a

Mathematics
2 answers:
steposvetlana [31]3 years ago
8 0

Answer:

2

Step-by-step explanation:

15-13=2

Phantasy [73]3 years ago
6 0

Answer:

2 yards

Step-by-step explanation:

subtract 13 from 15

15-13=2

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Help meeeeeeeeeeeeeeeee
Radda [10]

Answer:

c

Step-by-step explanation:

there are 8 parts and 4 of them are red= 4/8

which simplifies to 1/2

7 0
3 years ago
What is the opposite of -63
Evgesh-ka [11]

Answer:

63

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
How do you do inequalities
fgiga [73]
So some quick tips for inequalities:
**What you do to one side you HAVE TO do it to the other 2**
**If you ever divide a negative number past the inequality signs, the signs FLIP!!**
(e.g. 2>-5x>25)
-2/5 <x < -5

I hope that this has helped!
8 0
3 years ago
A triangle has an angle that measures 55°. The other two angles are in a ratio of 11:14. What are the measures of those two angl
koban [17]

9514 1404 393

Answer:

  55° : 70°

Step-by-step explanation:

The sum of the two other angles is ...

  180° -55° = 125°

The sum of the ratio units is 11+14 = 25. Each ratio unit stands for 125°/25 = 5°. Then the other two angles are ...

  11×5° = 55°

  14×5° = 70°

8 0
3 years ago
Read 2 more answers
If g(x)= x^2-2x-6 and h(x)= 2x^2-5x+2 find (h-g) (-2)
Natalka [10]

Answer:

<h2>(h - g)( - 2) = 18</h2>

Step-by-step explanation:

g(x) = x² - 2x - 6

h(x) = 2x² - 5x + 2

To find (h-g) (-2) we must first find h - g(x)

To find h - g(x) subtract g(x) from h(x)

We have

<h3>(h - g)(x) =  {2x}^{2}  - 5x + 2 - ( {x}^{2}  - 2x - 6)  \\  =  {2x}^{2}  - 5x + 2 -  {x}^{2}  + 2x + 6 \\  =  {2x}^{2}  -  {x}^{2}  - 5x + 2x + 2 + 6</h3><h3>(h - g)(x) =  {x}^{2}  - 3x + 8</h3>

To find (h-g) (-2) substitute the value of x that's - 2 into (h - g)(x) that's replace every x in (h - g)(x) by - 2

That's

<h3>(h - g)( - 2) =  ({ - 2})^{2}  - 3( - 2) + 8 \\  = 4 + 6 + 8 \\  = 10 + 8</h3>

We have the final answer as

<h3>(h - g)( - 2) = 18</h3>

Hope this helps you

7 0
4 years ago
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