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3 years ago

Simplify the expression: x2+x(x-5)-x+7

1 answer:

3 0

So to solve this equation we need to simplify the expression like so,
First write out the equation (I assume that you mean x2 as 2x)
2x+x(x-5)-x+7
Distribute
2x+x^2-5x-x+7
Combine like terms
-4x+x^2+7
And thats it! Enjoy!=)

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3 years ago

Let f (x) = 3x − 1 and ε > 0. Find a δ > 0 such that 0 < ∣x − 5∣ < δ implies ∣f (x) − 14∣ < ε. (Find the largest

s344n2d4d5 [400]

Answer:

This proves that f is continous at x=5.

Step-by-step explanation:

Taking f(x) = 3x-1 and $\varepsilon>0$ , we want to find a $\delta$ such that $|f(x)-14|$

At first, we will assume that this delta exists and we will try to figure out its value.

Suppose that $|x-5|$ . Then

$|f(x)-14| = |3x-1-14| = |3x-15|=|3(x-5)| = 3|x-5|< 3\delta$ .

Then, if $|x-5|$ , then $|f(x)-14|$ . So, in this case, if $3\delta \leq \varepsilon$ we get that $|f(x)-14|$ . The maximum value of delta is $\frac{\varepsilon}{3}$ .

By definition, this procedure proves that $\lim_{x\to 5}f(x) = 14$ . Note that f(5)=14, so this proves that f is continous at x=5.

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2 years ago

What should you do first in solving the quadratic equation?<br> x² + 18x + 81 = 25

N76 [4]

Answer:

x= -4,-14

Step-by-step explanation:

Try first to solve the equation by factoring. Be sure that your equation is in standard form before you start your factoring attempt.

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2 years ago

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Answer:

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3 years ago

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Elis [28]

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Step-by-step explanation:

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3 years ago