The product of two rational numbers is always rational because (ac/bd) is the ratio of two integers, making it a rational number.
We need to prove that the product of two rational numbers is always rational. A rational number is a number that can be stated as the quotient or fraction of two integers : a numerator and a non-zero denominator.
Let us consider two rational numbers, a/b and c/d. The variables "a", "b", "c", and "d" all represent integers. The denominators "b" and "d" are non-zero. Let the product of these two rational numbers be represented by "P".
P = (a/b)×(c/d)
P = (a×c)/(b×d)
The numerator is again an integer. The denominator is also a non-zero integer. Hence, the product is a rational number.
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Answer:
-16
Step-by-step explanation:
Given the sequence:
b(n)=b(n−1)−7, where b(1)=−2
b(2)=b(2−1)−7
=b(1)−7
=-2-7
b(2)=-9
Therefore, the 3rd term of the sequence
b(3)=b(3−1)−7
=b(2)-7 (Recall b(2)=-9 from above)
=-9-7
b(3)=-16
The 3rd term of the sequence is -16.
IF
2=5 ;
3=9 ; 3*5 - 3*2
4=48 ; 4*9 + 4*3
5=220 ; 5*48 - 5*4
6=1,350 6*220 + 6*5
7= 9408 7*1350 - 7*6
THEN 8 = 8*9408 + 8*7 = 75320
Answer:
the length in fraction form would be 16 1/2 rounded to the nearest 10 would be 20
Step-by-step explanation:
because 16.5=16 1/2
16.5=17
17=20
