2 years ago

A times a to the 7 power

Mathematics

1 answer:

ivolga24 [154]2 years ago

4 0

Answer:

${a}^{8}$

Step-by-step explanation:

a is a¹ and you have a^7 in multiplication you add the exponents. If you were to have a numerical value, you would replace a and calculate. If a = -5 then: a^8 =

$( - 5)^{8}$

which is = 390 625

You might be interested in

Look at the triangle: A right angle triangle is shown with hypotenuse equal to 10 centimeters. An acute angle of the triangle is

trasher [3.6K]

Tan x°= Opposite/ adjacent<span>so tan </span>x°=86

7 0

2 years ago

three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal

Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

= x + x + (x + $\frac{6}{5}$ ) = $\frac{27}{4}$

= 3x + $\frac{6}{5}$ = $\frac{27}{4}$

= 3x = $\frac{27}{4}$ - $\frac{6}{5}$

( let's take the LCM of 4 and 5 = 20

= 3x = $\frac{135}{20}$ - $\frac{24}{20}$

= 3x = $\frac{111}{20}$

= x = $\frac{111}{20}$ ÷ $\frac{3}{1}$ = $\frac{111}{20}$ × $\frac{1}{3}$ = $\frac{37}{20}$

So, the weight of the equal bags are $\frac{37}{20}$ and the weight of the third bag ( heavy one ) is $\frac{37}{20}$ + $\frac{6}{5}$ = $\frac{37}{20}$ + $\frac{24}{20}$ = $\frac{61}{20}$

1st bag = $\frac{37}{20}$ kg

2nd bag = $\frac{37}{20}$ kg

3rd bag = $\frac{61}{20}$ kg

Hope it helps...

7 0

2 years ago

an angle measure x degrees. what is the measure of its compliment? what is the measure of its supplement?

Strike441 [17]

The complement of 'x' degrees is (90 - x) degrees.

The supplement of 'x' degrees is (180 - x) degrees.

4 0

3 years ago

The ratio of corresponding sides of the first triangle to the second triangle below is

Cloud [144]

Answer:

Step-by-step explanation:

8 0

2 years ago

Factor the polynomial.<br> 5x4 + 10x3 + 15x2

Xelga [282]

Answer:

5x^2(x^2 + 2x + 3)

Step-by-step explanation:

All the terms can be factored by 5 and x^2, so we get:

5x^2(x^2 + 2x + 3)

there are no more common terms so this is the answer

8 0

2 years ago