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mojhsa [17]
3 years ago
9

A times a to the 7 power

Mathematics
1 answer:
ivolga24 [154]3 years ago
4 0

Answer:

{a}^{8}

Step-by-step explanation:

a is a¹ and you have a^7 in multiplication you add the exponents. If you were to have a numerical value, you would replace a and calculate. If a = -5 then: a^8 =

( - 5)^{8}

which is = 390 625

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Help me please! I’ll give brainliest
mojhsa [17]

Answer:

The Answer is J because 1 1/2 or 1.5 times itself equals 2 1/4 or 2.25

3 0
3 years ago
Read 2 more answers
SUPER EASY WILL GIVE BRAINLEIST IF DONE BEFORE 10 PM PLS HURRY. IF U HAVE TIME PLS HELP ME ON OTHER QUESTIONS THANK YOU <3
andrew11 [14]

Answer:

1. new perimeter = 4 times the old perimeter

2. The area will go up by a factor of 16

3. The new area is 1/9 of the original area.

Step-by-step explanation:

1. side length1 = x

side length2 = y

2x + 2y = perimeter

2(4x) + 2(4)y = new perimeter

8x + 8y = new perimeter

new perimeter = 4 times the old perimeter

2. The area will go up by a factor of 16. This is because the area formula has them being multiplied together and thus it will make the area go up by that much.

3. Let the length of the rectangle be x

Let width of rectangle be y

Area of rectangle =  L*W

Now Each side length of the rectangle is multiplied by 1/3

So, new area =  (1/3)L * (1/3)W

=(1/9)LW

So, the new area is 1/9 of the original area.

7 0
3 years ago
A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5
lara [203]

Answer:

7.3% of the bearings produced will not be acceptable

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 0.499, \sigma = 0.002

Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.

So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.

Larger than 0.504

1 subtracted by the pvalue of Z when X = 0.504.

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.504 - 0.494}{0.002}

Z = 2.5

Z = 2.5 has a pvalue of 0.9938

1 - 0.9938= 0.0062

Smaller than 0.496

pvalue of Z when X = -1.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.496 - 0.494}{0.002}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.0668 + 0.0062 = 0.073

7.3% of the bearings produced will not be acceptable

4 0
3 years ago
Can you please answer the question? Thank you so much.
pychu [463]

Answer:

bruh

Step-by-step explanation:

4 0
3 years ago
12 divided by the sum of h and 2
irinina [24]
Putting this into expression form, it would be: 
12 ÷ (h + 2) 
Hope this helps!
6 0
3 years ago
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