All categories

1 year ago

Evaluate the expression for x = 2 and y = 4.

Mathematics

1 answer:

Lelu [443]1 year ago

7 0

Answer:

Not enough info

Step-by-step explanation:

Not enough info sry

You might be interested in

Andrea has 1/4 of a sack of rice. She divides the rice equally

olga nikolaevna [1]

Answer:

1/28 of the sack

Step-by-step explanation:

3 0

2 years ago

Help!!! Will give brainliest to correct answer.....

zlopas [31]

I believe the answer is C.

93.53 - 21.41 = 72.12

If you simplify C, its answer becomes equivalent to the answer of the original problem:

(90 - 20) + (3 - 1) + (0.5 - 0.4) + (0.03 - 0.01)

70 + 2 + 0.1 + 0.02

72.12

7 0

3 years ago

Find the 12th term of the given explicit geometric formula.<br> f(n) =3(2)^ n-1

morpeh [17]

Answer:

Step-by-step explanation:

5 0

3 years ago

Consider the following region R and the vector field F. a. Compute the two-dimensional curl of the vector field. b. Evaluate bo

Shalnov [3]

Looks like we're given

$\vec F(x,y)=\langle-x,-y\rangle$

which in three dimensions could be expressed as

$\vec F(x,y)=\langle-x,-y,0\rangle$

and this has curl

$\mathrm{curl}\vec F=\langle0_y-(-y)_z,-(0_x-(-x)_z),(-y)_x-(-x)_y\rangle=\langle0,0,0\rangle$

which confirms the two-dimensional curl is 0.

It also looks like the region $R$ is the disk $x^2+y^2\le5$ . Green's theorem says the integral of $\vec F$ along the boundary of $R$ is equal to the integral of the two-dimensional curl of $\vec F$ over the interior of $R$ :

$\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\iint_R\mathrm{curl}\vec F\,\mathrm dA$

which we know to be 0, since the curl itself is 0. To verify this, we can parameterize the boundary of $R$ by

$\vec r(t)=\langle\sqrt5\cos t,\sqrt5\sin t\rangle\implies\vec r'(t)=\langle-\sqrt5\sin t,\sqrt5\cos t\rangle$

$\implies\mathrm d\vec r=\vec r'(t)\,\mathrm dt=\sqrt5\langle-\sin t,\cos t\rangle\,\mathrm dt$

with $0\le t\le2\pi$ . Then

$\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\int_0^{2\pi}\langle-\sqrt5\cos t,-\sqrt5\sin t\rangle\cdot\langle-\sqrt5\sin t,\sqrt5\cos t\rangle\,\mathrm dt$

$=\displaystyle5\int_0^{2\pi}(\sin t\cos t-\sin t\cos t)\,\mathrm dt=0$

7 0

3 years ago

Martina spends $15 each time she travels the toll roads. She started the month with $225 in her toll road account. The amount, A

PolarNik [594]

Answer:

$70 is what he would have left. Since each trip is $14 you would multiply that by the amount of times he went which was 11. 14x11 is $154. But you need what he has left so you take his total amount $224-$154 and get $70.

Part b.) 16 times. He has $224 total. You want to find out how many times he can go on the tool roads. We know the toll roads cost $14 each time. So you do $224/14 and get an even amount of 16. He would be able to use it 16 times before he have no money left.

Step-by-step explanation:

6 0

2 years ago