Ask question

Ask question

All categories

3 years ago

6

-

1 answer:

babunello [35]3 years ago

5 0

Answer:

a) increases

Explanation:

The increase in temperature causes the particles to move much faster. This in turn effects the collision rate of the particle which causes the chemical reaction. Thus the rate of chemical reaction increases.

So, we conclude that the rate of a chemical reaction is directly related to temperature. With increase in temperature there is an increase in the reaction rate and vice versa.

You might be interested in

Which one of the following statements does not accurately describe vibrations?

Paladinen [302]

A. Forced vibrations, such as those between a tuning fork and a large cabinet surface, result in a much lower sound than was produced by the original vibrating body.

4 0

3 years ago

Soapy water between surfaces

Inessa [10]

Answer:

<em>A</em><em>.</em><em>increases</em><em> </em><em>friction</em>

Explanation:

6 0

2 years ago

Read 2 more answers

The boy moving down the hill posses what energy?

elena-s [515]

Answer: Kinetic energy

Explanation:

Kinetic energy and potential energy can change forms. For example, the car moving up the hill is kinetic energy

6 0

3 years ago

Read 2 more answers

If we assume that, in the African savanna, the predator population remains constant, what other, nonmobile, factor would influen

musickatia [10]

On usa test prep the answer is c

7 0

3 years ago

Read 2 more answers

When a voltage difference is applied to a piece of metal wire, a current flows through it. if this metal wire is now replaced wi

Nikitich [7]

The resistance of the cylindrical wire is $R=\frac{\rho l}{A}$ .

Here $R$ is the resistance, $l$ is the length of the wire and $A$ is the area of cross section. Since the wire is cylindrical $A=\frac{\pi d^2}{4}$ .

Comparing two wires,

$R_1=\frac{\rho_1 l}{A_1} \\ R_2=\frac{\rho_2 l}{A_2}$

Dividing the above 2 equations,

$\frac{R_1}{R_2}=\frac{\rho_1 }{\rho_2} \frac{A_2 }{A_1} \\ \frac{R_1}{R_2}=\frac{\rho_1 }{\rho_2} \frac{d_2^2 }{d_1^2} \\$

Since $d_2=2d_1$

The above ratio is

$\frac{R_1}{R_2}=\frac{1.68(10^{-8}) }{1.59(10^{-8}) } (4)\\ \frac{R_1}{R_2}=4.2264$

We also have,

$\frac{E/R_1}{E/R_2} =\frac{I_1}{I_2} \\ I_2=\frac{R_1}{R_2}I_1 \\ I_2=4.23I_1$

The current through the Silver wire will be 4.23 times the current through the original wire.

8 0

3 years ago