All categories

2 years ago

A 6V radio with a current of 2A is turned on for 5 minutes. Calculate the energy transferred in joules

Physics

1 answer:

iogann1982 [59]2 years ago

7 0

Answer:

R=V/I=6/2=3ohm

time =5minutes =5*60=300seconds

I=2A

Heat =I^2Rt=(2)^2*3*300=4*900=3600J

You might be interested in

What could contribute to an inaccurate vital sign reading?

amid [387]

<span>Lack of training in getting the vital sign or worst, not knowing the right way to take the vital sign could contribute to an inaccurate vital sign reading. For example, if you are tasked to get the respiration of the patient, the rule is to count inhale and exhale as one. But if you were not able to know this rule, and you counted inhale as one and exhale as another, this could impair the vital reading. </span>

7 0

3 years ago

Which is the fundamental law of energy?

Mkey [24]

Energy cannot be created nor be destroyed

6 0

3 years ago

Read 2 more answers

1.An electrician is deciding what type of material to use for wires. Based on the periodic table, which of the following would b

Alinara [238K]

Without specifics, the best element to conduct electricity would be copper.

5 0

3 years ago

Imagine that you are approaching a black hole in a spacecraft. what would you see? what would happen to you?

Vladimir79 [104]

You will see some thing pitch black pulling you. you will feel an immense pull or attraction while going rapidly inside the black hole.

3 0

2 years ago

A 12000 kg railroad car is traveling at a 2 m/s when it strikes another 10000 kg railroad is at rest. If the car lock together w

zimovet [89]

The final speed is $1.09m\frac{m}{s}$

Why?

To calculate the final speed, we need to know that we are working with an inelastic collision, it means that both bodies stick together after the colission. We can calculate the final speed of the bodies (if exists) using the following equation:

$m_{1}v{1}+m_{2}v_{2}=(m_{1}+m_{2})v_{f}$

We are given the following information:

$m_{1}=12000kg\\v_{1}=2\frac{m}{s}\\m_{2}=10000kg\\v_{2}=0\frac{m}{s}(at rest)$

So, substituting and calculating, we have:

$m_{1}v{1}+m_{2}v_{2}=(m_{1}+m_{2})v_{f}\\\\12000kg*2\frac{m}{s}+10000kg*0\frac{m}{s}=(12000kg+10000kg)*v_{f}\\\\v_{f}=\frac{24000\frac{kg.m}{s} }{22000kg}=1.09m\frac{m}{s}$

Hence, the final speed is 1.09 m/s.

Have a nice day!

5 0

3 years ago