<h2>When two object P and Q are supplied with the same quantity of heat, the temperature change in P is observed to be twice that of Q. The mass of P is half that of Q. The ratio of the specific heat capacity of P to Q</h2>
Explanation:
Specific heat capacity
It is defined as amount of heat required to raise the temperature of a substance by one degree celsius .
It is given as :
Heat absorbed = mass of substance x specific heat capacity x rise in temperature
or ,
Q= m x c x t
In above question , it is given :
For Q
mass of Q = m
Temperature changed =T₂/2
Heat supplied = x
Q= mc t
or
X=m x C₁ X T₁
or, X =m x C₁ x T₂/2
or, C₁=X x 2 /m x T₂ (equation 1 )
For another quantity : P
mass of P =m/2
Temperature= T₂
Heat supplied is same that is : X
so, X= m/2 x C₂ x T₂
or, C₂=2X/m. T₂ (equation 2 )
Now taking ratio of C₂ to c₁, We have
C₂/C₁= 2X /m.T₂ /2X /m.T₂
so, C₂/C₁= 1/1
so, the ratio is 1: 1
According to the given statement:
- The frequency response does not change, which is the first thing we notice.
- The new resistance at the resonance point causes a reduction in the circuit's current flow.
- Z = R + R₂
<h3>The definition of series circuits:</h3>
electrical circuit. The path that the entire current takes as it passes through each component makes up a series circuit. Branching is used in parallel circuits to divide the current and limit the amount that flows through each branch.
<h3>How does a series circuit operate?</h3>
According to this definition, there are three principles of series circuits: all parts share the same current, resistances add up to a larger total resistance, and voltage drops add up to a larger total voltage. In the definition of a series circuit, all of these guidelines have their origin.
<h3>According to the given information:</h3>
The impedance of a series circuit is
Z₀² = R² + (X
-X
) ²
The initial resistance impedance shifts to when we add another resistor to the series
Z² = (R + R₂) ² + (X
- X
) ²
Let's examine this sentence.
- The frequency response remains unchanged, which is the first thing we notice.
- The new resistance at the resonance point causes the circuit's current to decrease.
Z = R + R₂
To know more about electrical circuit visit:
brainly.com/question/1922668
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fraction equation is<span>
F =µR
F=friction,µ=coefficient , R=reaction = mg
use same equation for b part, but the reaction is no longer mg because the plain is now inclined. Draw a forces diagram and you will see that the reaction force can be calculated from the weight of the object and inclination of the plain using trigonometry.</span>
44.64m
Explanation:
Given parameters:
Mass of the car = 1500kg
Initial velocity = 25m/s
Frictional force = 10500N
Unknown:
Distance moved by the car after brake is applied = ?
Solution:
The frictional force is a force that opposes motion of a body.
To solve this problem, we need to find the acceleration of the car. After this, we apply the appropriate motion equation to solve the problem.
-Frictional force = m x a
the negative sign is because the frictional force is in the opposite direction
m is the mass of the car
a is the acceleration of the car
a =
=
= -7m/s²
Now using;
V² = U² + 2as
V is the final velocity
U is the initial velocity
a is the acceleration
s is the distance moved
0² = 25² + 2 x 7 x s
0 = 625 - 14s
-625 = -14s
s = 44.64m
learn more:
Velocity problems brainly.com/question/10932946
#learnwithBrainly
The new period is D) √2 T
![\texttt{ }](https://tex.z-dn.net/?f=%5Ctexttt%7B%20%7D)
<h3>Further explanation</h3>
Let's recall Elastic Potential Energy and Period of Simple Pendulum formula as follows:
![\boxed{E_p = \frac{1}{2}k x^2}](https://tex.z-dn.net/?f=%5Cboxed%7BE_p%20%3D%20%5Cfrac%7B1%7D%7B2%7Dk%20x%5E2%7D)
where:
<em>Ep = elastic potential energy ( J )</em>
<em>k = spring constant ( N/m )</em>
<em>x = spring extension ( compression ) ( m )</em>
![\texttt{ }](https://tex.z-dn.net/?f=%5Ctexttt%7B%20%7D)
![\boxed{T = 2\pi \sqrt{ \frac{L}{g} }}](https://tex.z-dn.net/?f=%5Cboxed%7BT%20%3D%202%5Cpi%20%5Csqrt%7B%20%5Cfrac%7BL%7D%7Bg%7D%20%7D%7D)
where:
<em>T = period of simple pendulum ( s )</em>
<em>L = length of pendulum ( m )</em>
<em>g = gravitational acceleration ( m/s² )</em>
Let us now tackle the problem!
![\texttt{ }](https://tex.z-dn.net/?f=%5Ctexttt%7B%20%7D)
<u>Given:</u>
initial length of pendulum = L₁ = L
initial mass = M₁ = M
final length of pendulum = L₂ = 2L
final mass = M₂ = 2M
initial period = T₁ = T
<u>Asked:</u>
final period = T₂ = ?
<u>Solution:</u>
![T_1 : T_2 = 2\pi \sqrt{ \frac{L_1}{g} }} : 2\pi \sqrt{ \frac{L_2}{g} }}](https://tex.z-dn.net/?f=T_1%20%3A%20T_2%20%3D%202%5Cpi%20%5Csqrt%7B%20%5Cfrac%7BL_1%7D%7Bg%7D%20%7D%7D%20%3A%202%5Cpi%20%5Csqrt%7B%20%5Cfrac%7BL_2%7D%7Bg%7D%20%7D%7D)
![T_1 : T_2 = \sqrt{L_1} : \sqrt{L_2}](https://tex.z-dn.net/?f=T_1%20%3A%20T_2%20%3D%20%5Csqrt%7BL_1%7D%20%3A%20%5Csqrt%7BL_2%7D)
![T : T_2 = \sqrt{L} : \sqrt{2L}](https://tex.z-dn.net/?f=T%20%3A%20T_2%20%3D%20%5Csqrt%7BL%7D%20%3A%20%5Csqrt%7B2L%7D)
![T : T_2 = 1 : \sqrt{2}](https://tex.z-dn.net/?f=T%20%3A%20T_2%20%3D%201%20%3A%20%5Csqrt%7B2%7D)
![\boxed {T_2 = \sqrt{2}\ T}](https://tex.z-dn.net/?f=%5Cboxed%20%7BT_2%20%3D%20%5Csqrt%7B2%7D%5C%20T%7D)
![\texttt{ }](https://tex.z-dn.net/?f=%5Ctexttt%7B%20%7D)
<h3>Learn more</h3>
![\texttt{ }](https://tex.z-dn.net/?f=%5Ctexttt%7B%20%7D)
<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Elasticity