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creativ13 [48]
2 years ago
8

A T-shirt is launched at an angle of 30° with an initial velocity of 25 m/s how long does it take to reach the peak? How long is

it in the air for totally?
Physics
1 answer:
sweet-ann [11.9K]2 years ago
4 0

Answer:

The launched angle θ = 30 degrees, the initial velocity Vo = 20 m/s, the initial horizontal velocity Vox= ?, the initial vertical velocity Voy = ?, the time of flight t = ? the maximum height h = ?

Vox = Vo * (cos of 30 degrees)

Voy = Vo * (sin of 30 degrees)

t = 2 * (Voy / g)

h = Voy * 0.5 t - 1/2 g * (0.5t)^2

I have given the equations for you to use, just plug – in the values and then solve in a step by step manner.

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The graph below represents changes in water. What process is occurring during section “B” of the graph?
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The scientific inquiry process
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3 years ago
Your heart pumps blood at a pressure of 100 mmHg and flow speed of 60 cm/s. At your brain, the blood enters capillaries with suc
Savatey [412]

Answer:

1.28 m

Explanation:

Generally, pressure of fluid is given by

P=\rho g h where g is acceleration due to gravity, h is the height and \rho is the density

Considering that the pressure for mercury is same as for blood only that the height and density of fluid are different then

\rho_b g h_b= \rho_m g h_m

Since g is constant, then

\rho_b h_b= \rho_m h_m

Making h_b the subject of the formula then

h_b=\frac {\rho_m h_m}{\rho_b}

Where subscripts m and b denote mercury and blood respectively

Assuming density of blood is 1060 Kg/m3, density of mercury as 13600 Kg/m3 and substituting height of mercury for 0.1 m then

h_b=\frac {13600*0.1}{1060}=1.283018868  m \approx 1.28 m

7 0
3 years ago
A hungry 169169 kg lion running northward at 77.377.3 km/hr attacks and holds onto a 31.731.7 kg Thomson's gazelle running eastw
navik [9.2K]

Answer:  75,242.9 m/s

Explanation:

from the question we are given the following parameters

mass of Lion (ML) = 169,169 kg

velocity of lion (VL) = 777,377.7 m/s

mass of Gazelle (Mg) = 31,731.7 kg

velocity of Gazelle (Vg) = 63,863.8 kg

mass of Lion and Gazelle (M) = 200,900.7 kg

velocity of Lion and Gazelle (V) = ?

The first figure below shows the motion of the Lion and Gazelle with their direction.

The second diagram shows the motion of the Lion and Gazelle with their directions rearranged to form a right angle triangle.

from the triangle formed we can get the velocity of the Lion and Gazelle immediately after collision using their momentum and Phytaghoras theorem

momentum = mass x velocity

momentum of the Lion = 169,169 x 77,377.3 = 13,089,840,463.7 kgm/s

momentum of the Gazelle = 31,731.7 x 63,863.8 = 2,026,506,942.46 kgm/s

momentum of the Lion and Gazelle = 200,900.7  x V

now applying Phytaghoras theorem we have

13,089,840,463.7 + 2,026,506,942.46 =  200,900.7 x V

15,116,347,406.16 = 200,900.7 x V

V = 75,242.9 m/s

7 0
2 years ago
Read 2 more answers
How does the lever arm change if you decrease the angle of the force?
Vladimir79 [104]

Answer:

The lever arm could decrease or increase depending of the initial angle.

Explanation:

The lever arm d is calculated by:

d = rsin(θ)

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So, the increse or decrees of d depends of the sin of the angle θ, if the initial angle is greather than 90° and the angle decrease to an angle closer to 90°, the lever arm will increase but if the initial angle is 90° or lower and the angle decrease, the lever arm will decrease.

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The way light bounces off a minerals surface is described by the minerals?
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Luster I think is what you are looking for
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