A(n) = a₁.(r)ⁿ⁻¹, where a₁ = 1st term, r= common ratio and n, the rank
In the formula given a₁ = 5, r = 3/2 and n = 6 (we have to find the 6th term value).
a₆ = 5.(3/2)⁶⁻¹ = 5.(3/2)⁵ = 1215/32 (answer C)
Yes. The two theorems are equivalent statements given that the fundamental theorem of calculus is true.
so we have a table of values, with x,y coordinates, so let's use any two of those points to get the slope of the table and use the point-slope form to get its equation
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Remark
The quick answer is C does not represent a function. It has two y values for x = 2. These two points are (2,1) and (2,3). That eliminates C. No x can have 2 y values and be called a function. A function can have many x vales for a single y and still be a function.
A has all different x values, so it could be classed as a function. There are no values where x has more than 1 y value.
B also has all different x values. It too is a function.
Answer
A and B are both functions. C is not.
D <<<<< Answer
The correct answer among the choices listed above is the second option. <span>The following system of equations is equivalent. This is because when written in the same form, one equation will yield to the same equation as the other.
</span>y = -1/3x +2/3
<span>2x + 6y = 4
</span>6y = 4 - 2x
y = 2/3 - 1/3x
<span>y = -1/3x +2/3 </span>