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3 years ago

What is the perimeter of the rectangle in the coordinate plane?

Mathematics

2 answers:

Zinaida [17]3 years ago

6 0

It's (10-7)=3 wide and (17-7)=10 high

So the perimeter is

P=2(3+10)=26 units

sukhopar [10]3 years ago

3 0

Length is 9 squares and the Width is 3 squares.
9+3+9+3=?
9+9+6=?
18+6=?
24

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MissTica

The answer is #2. 3/2. The dot rises 3 lines and moves to the right 2 lines.

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3 years ago

How many 3cm cubes can be put in a box 3cm long 6cm wide 12cm high?

lisov135 [29]

Answer:

Step-by-step explanation:

A cube is equal on all sides. Therefore the cubes must be 3cm x 3cm x 3cm. Therefore, each cube has an area of 27cm^3. The box that the cube has an area in is 3cm x 6cm x 12 cm which = 216cm^3. If you do $216cm^3/27cm^3 = 8 cubes$

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2 years ago

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Pls help I need this I’m begging you

Stells [14]

Answer:

Option H

Step-by-step explanation:

y = 3x - 4

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3 years ago

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Vilka [71]

Answer: Part A - C, Part B - 12 pieces

Step-by-step explanation:

Part A:

We know that 1/4 of Meredith's sub is bigger than 1/4 of Jim's sub, so we can set up an inequality.

Let Meredith's sub size = m; Jim's = j

Therefore, 1/4*m > 1/4*j

We can multiply both sides by 4:

m > j

Thus, the correct answer is C

Part B:

Since he had 1/4 of it left, that means he at 1 - 1/4 of it = 3/4 of his sub.

We can calculate the value of 3/4 * 16 = 12 pieces

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3 years ago

Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s

Nataliya [291]

Answer:

$f(x)=\frac{1}{2}x^2-4x+5$

Step-by-step explanation:

A parabola is written in the form

$f(x)=a((x-h)^2+k)$ (1)

where:

$h$ is the x-coordinate of the vertex of the parabola

$ak$ is the y-coordinate of the vertex of the parabola

$a$ is a scale factor

For the parabola in the problem, we know that the vertex has coordinates (4,-3), so we have:

$h=4$ (2)

$ak=-3$

From this last equation, we get that $a=\frac{-3}{k}$ (3)

Substituting (2) and (3) into (1) we get the new expression:

$f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3$ (4)

We also know that the parabola contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

$-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6$

So we also get:

$a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}$

So the equation of the parabola is:

$f(x)=\frac{1}{2}((x-4)^2 -6)$ (5)

Now we want to rewrite it in the standard form, i.e. in the form

$f(x)=ax^2+bx+c$

To do that, we simply rewrite (5) expliciting the various terms, we find:

$f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5$

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3 years ago