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Norma-Jean [14]
2 years ago
8

How many 3cm cubes can be put in a box 3cm long 6cm wide 12cm high?

Mathematics
2 answers:
lisov135 [29]2 years ago
7 0

Answer:

8

Step-by-step explanation:

A cube is equal on all sides. Therefore the cubes must be 3cm x 3cm x 3cm. Therefore, each cube has an area of 27cm^3. The box that the cube has an area in is 3cm x 6cm x 12 cm which = 216cm^3. If you do 216cm^3/27cm^3 = 8 cubes

GREYUIT [131]2 years ago
3 0
The number of cubes that fit on the 3 cm side times the number that fit on the 6 cm side times the number that fit in the 12 cm high side.
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Change 1 hour 25 minutes 29 seconds to seconds
Orlov [11]

Answer:

remember

1h=60min

1min=60 sec

now come to the question

1h=60min

1min=60 sec

60min=60×60=3600sec in 1hour

25min=60×25=1500sec in 25 min

total all sec=3600+1500+29=5129sec

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
−6x + 14 < −28 OR 9x + 15 ≤ −12. solve for x.
sasho [114]

Answer:

x>7 or x ≤ -3

Step-by-step explanation:

Solving the 1st inequality

-6x +14 < -28 --------------- (Collect like terms)

-6x < -28 - 14

-6x < - 42 -------------------- (Divide both sides by -6)

Note: If you decide an inequality expression by a negative value, the inequality sign changes)

-6x/-6 > -42/-6

x > 7

Solving the 2nd inequality

9x + 15 ≤ −12 ----------- (Collect like terms)

9x ≤ −12 - 15

9x ≤ −27 ------------------(Divide both sides by 9)

9

9x/9 ≤ −27/9

x ≤ -3

Bring both results together, we get

x>7 or x ≤ -3

The final result is complex (i.e. can't be combined together).

4 0
3 years ago
T<br> ✓<br> Х<br> Find the sum of (x2 – 7x + 5) and (-3x2 - x + 10)<br> [
Zanzabum

Answer:

-2x² - 8x + 15 = 0

Step-by-step explanation:

Given the following algebraic expression;

x² – 7x + 5

-3x² - x + 10

To add the equation together;

x² – 7x + 5 + (-3x² - x + 10) = 0

x² – 7x + 5 - 3x² - x + 10 = 0

Collecting like terms, we have;

(x² - 3x²) - (7x + x) + (5 + 10) = 0

-2x² - 8x + 15 = 0

8 0
3 years ago
Dal
iogann1982 [59]

Answer:a

Step-by-step explanation:

6 0
3 years ago
Eliminate the parameter. x = 1/2t, y = 3t^3 - 1
Elis [28]
X = t/2. t = 2x
y = 3t^3 - 1
y = 3(2x)^3 -1

y = 24x^3 -1
4 0
3 years ago
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