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2 years ago

Please help I think its 16 but not sure

Mathematics

1 answer:

Stels [109]2 years ago

6 0

Answer:

I think its 12 to this question

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25 is 36% of what number

ch4aika [34]

Answer:

x = 69.44

Step-by-step explanation:

We have, 36% × x = 25

or, 36/100 × x = 25

Multiplying both sides by 100 and dividing both sides by 36,

we have x = 25 × 100/36

x = 69.44

If you are using a calculator, simply enter 25×100÷36, which will give you the answer.

4 0

1 year ago

Plz help fast solve this

torisob [31]

Answer:

Step-by-step explanation:

Math simplification

4 0

2 years ago

Read 2 more answers

Help plz I really need help could you show your work if you do it plz.

Vika [28.1K]

What do you need help with?

7 0

3 years ago

Find the cost function for the marginal cost function. C(x) =0.06 e 0.08x; fixed cost is $10 C(x)=_______

sashaice [31]

Answer:

The cost function for $C(x) = 0.06\cdot e^{0.08\cdot x}$ is $c(x) = 0.75\cdot e^{0.08\cdot x}+10$ .

Step-by-step explanation:

The marginal cost function ( $C(x)$ ) is the derivative of the cost function ( $c(x)$ ), then, we should integrate the marginal cost function to find the resulting expression. That is:

$c(x) = \int {C(x)} \, dx + C_{f}$

Where:

$C_{f}$ - Fixed costs, measured in US dollars.

If we know that $C(x) = 0.06\cdot e^{0.08\cdot x}$ and $C_{f} = \$\,10$ , then:

$c(x) = 0.06\int {e^{0.08\cdot x}} \, dx + 10$

$c(x) = 0.75\cdot e^{0.08\cdot x}+10$

The cost function for $C(x) = 0.06\cdot e^{0.08\cdot x}$ is $c(x) = 0.75\cdot e^{0.08\cdot x}+10$ .

3 0

3 years ago

1. The number of rabbits on an island is increasing exponentially.

Zina [86]

Answer:

<em>There are approximately 114 rabbits in the year 10</em>

Step-by-step explanation:

<u>Exponential Growth </u>

The natural growth of some magnitudes can be modeled by the equation:

$P=P_o(1+r)^t$

Where P is the actual amount of the magnitude, Po is its initial amount, r is the growth rate and t is the time.

We are given two measurements of the population of rabbits on an island.

In year 1, there are 50 rabbits. This is the point (1,50)

In year 5, there are 72 rabbits. This is the point (5,72)

Substituting in the general model, we have:

$50=P_o(1+r)^1$

$50=P_o(1+r)\qquad\qquad[1]$

$72=P_o(1+r)^5\qquad\qquad[2]$

Dividing [2] by [1]:

$\displaystyle \frac{72}{50}=(1+r)^{5-1}=(1+r)^{4}$

Solving for r:

$\displaystyle r=\sqrt[4]{\frac{72}{50}}-1$

Calculating:

r=0.095445

From [1], solve for Po:

$\displaystyle P_o=\frac{72}{(1+r)^5}$

$\displaystyle P_o=\frac{72}{(1.095445)^5}$

$P_o=45.64355$

The model can be written now as:

$P=45.64355(1.095445)^t$

In year t=10, the population of rabbits is:

$P=45.64355(1.095445)^{10}$

P = 113.6

$P\approx 114$

There are approximately 114 rabbits in the year 10

5 0

2 years ago