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3 years ago

Simplify the fraction 35/21 in simplest form

Mathematics

2 answers:

aev [14]3 years ago

7 0

Answer:

5/3

Step-by-step explanation:

35 and 21 could be divided by a factor of 7.

35 ÷ 7 = 5

21 ÷ 7 = 3

So,

35/21 = 5/3

djverab [1.8K]3 years ago

5 0

Answer:

5/3

Step-by-step explanation:

35 divided by 7 is 5

21 divided by 7 is 3

Thus 35/21 in simplest form is 5/3

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Jolie earned $205 for babysitting in one month. She spent d dollars going to a water park with some friends. After going to the

jok3333 [9.3K]

205 - d = 160

Add d to both sides of the equation

205 = 160 + d

Subtract 160 from each side

45 = d

Jolie spent $45 at the water park.

8 0

4 years ago

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Write two expressions with unlike denominators whose sum is x-3/x+2, I need help it is confusing for me.

skad [1K]

Answer:

$\displaystyle A=\frac{x-2}{x+3}$

$\displaystyle B=\frac{-5}{(x+3)(x+2)}$

Step-by-step explanation:

We need to find two expressions with unlike denominators what sum

$\displaystyle S=\frac{x-3}{x+2}$

Let's suppose one of the expressions is:

$\displaystyle A=\frac{x-2}{x+3}$

Now we subtract S minus A to find the other expression B:

$\displaystyle B=S-A=\frac{x-3}{x+2}-\frac{x-2}{x+3}$

Multiply the first fraction by x+3 and the second by x+2;

$\displaystyle B=(x+3)\frac{x-3}{(x+3)(x+2)}-(x+2)\frac{x-2}{(x+3)(x+2)}$

Operating:

$\displaystyle B=\frac{x^2-9}{(x+3)(x+2)}-\frac{x^2-4}{(x+3)(x+2)}$

Subtracting both fractions with like denominators:

$\displaystyle B=\frac{x^2-9-(x^2-4)}{(x+3)(x+2)}$

Simplifying:

$\displaystyle B=\frac{-5}{(x+3)(x+2)}$

Thus the two expressions are:

$\displaystyle A=\frac{x-2}{x+3}$

And

$\displaystyle B=\frac{-5}{(x+3)(x+2)}$

8 0

3 years ago

Given the foci of (8,0) and the difference of the focal radii = 6, find the equation of the hyperbola

k0ka [10]

Given :

The foci of hyperbola are (8,0) and (-8,0) .

The difference of the focal radii = 6.

To Find :

The equation of the hyperbola.

Solution :

We know, distance between foci is given by :

2c = 8 - (-8)

c = 8

Also, difference between the foci or focal distance is given by :

2a = 6

a = 3

Now, we know for hyperbola :

$b^2 +a^2 = c^2\\\\b^2={c^2-a^2}\\\\b^2 = 64-9\\\\b^2 = 55$

General equation of hyperbola is :

$\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1\\\\\dfrac{x^2}{9}+ \dfrac{y^2}{55}=1$

Hence, this is the required solution.

3 0

3 years ago

How would i do both of these, show work pls

Alex_Xolod [135]

Answer:

-12.5%

-14.29%

Step-by-step explanation:

For #2:

Original price is $2.00, that price decreased by $0.25 is $1.75. First figure out what $0.25 out of $2.00 is as a percent:

0.25/2.00 = 0.125 = 12.5%

Then, since the price DECREASED by $0.25, the percent would be negative.

For #4:

Original price is $3.50, that price decreased by $0.50 is $3.00. Like #2, you need to figure out what $0.50 out of $3.50 is as a percent:

0.50/3.50 = 0.1429 = 14.29%

Then, since the price DECREASED by $0.50, the percent would be negative.

3 0

3 years ago

Only answer if you’re sure :) thank you

adelina 88 [10]

Your answer is 1/2
Hope this helps!

3 0

3 years ago

Read 2 more answers

Simplify the fraction 35/21 in simplest form​

Simplify the fraction 35/21 in simplest form