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Oksanka [162]
3 years ago
15

Rewrite the equation 10=1,000 with an exponet that makes it true .​

Mathematics
2 answers:
Rzqust [24]3 years ago
8 0

Answer:

10^3=1,000

Step-by-step explanation:

The expression 10=1,000 is obviously false, but we can make it true by rewriting it with an exponent.

Note that 1,000=10*10*10

Or, equivalently:

1,000=10^3

Thus, if we modify the original false expression and add an exponent 3 to the base 10, then it would be true:

Original:

10=1,000 => false

Rewritten true:

\boxed{10^3=1,000}

inn [45]3 years ago
4 0
10^3= 1,000
hope this helps :)
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The corner is 60°, and based on the information given it is D...but if you can measure the angle, it would be B... A and C assume different sizes.
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Triangle XYZ has vertices at X(–2, –1), Y(–3, –6), and Z(–7, –5). If triangle XYZ is rotated 90° clockwise, what will be the coo
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Answer:1. Is right 3 down 5, because to get from x(0,0) to x'(3,-5), you need I shift to the right 3 and downwards 5.

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3. Clockwise 90 degrees. Going counter clock wise 270 degrees is like going around 3/4 of a circle (because 270/360 is 3/4). Just as well, going clock wise 90 degrees is like going 1/4 of the circle, but in the opposite direction. This means they will both land at the same point.

Hope this Helps!

Step-by-step explanation:

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3 years ago
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An airplane flies due north from ikeja airport for 500km.It then flies on a bearing of 060 from a further distance of 300km befo
Nata [24]

Answer:

482 km

63.94 degrees

Step-by-step explanation:

to solve this question we will use the cosine rule. For starters, draw your diagram. From point A, up north is 500km and 060 from there, another 300. If you join the point from the road junction back to the starting point, yoou have a triangle.

Cosine rule states that

C = \sqrt{A^{2} + B^{2} -2AB   cos(c)  }

where both A and B are the given distances, 500 and 300 respectively, C is the 3rd distance we're looking for and c is the given angle, 060

solving now, we have

C = \sqrt{500^{2} + 300^{2} -2 * 500 * 300 cos(60)  }

C = \sqrt{250000 + 90000 - [215000   cos(60)  }]

C = \sqrt{340000 - [215000 * 0.5  }]

C = \sqrt{340000 - [107500  }]

C =\sqrt{232500}

C = 482 km

The bearing can be gotten by using the Sine Rule.

\frac{sina}{A} = \frac{sinc}{C}

sina/500 = sin60/482

482 sina = 500 sin60

sina = \frac{500 sin60}{482}

sina = 0.8983

a = sin^-1(0.8983)

a = 63.94 degrees

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Two boats leave a dock at the same time. One boat travels south at 32 mi divided by hr32 mi/hr and the other travels east at 60
TEA [102]

Answer: the rate at which the distance between the boats is​ increasing is 68 mph

Step-by-step explanation:

The direction of movement of both boats forms a right angle triangle. The distance travelled due south and due east by both boats represents the legs of the triangle. Their distance apart after t hours represents the hypotenuse of the right angle triangle.

Let x represent the length the shorter leg(south) of the right angle triangle.

Let y represent the length the longer leg(east) of the right angle triangle.

Let z represent the hypotenuse.

Applying Pythagoras theorem

Hypotenuse² = opposite side² + adjacent side²

Therefore

z² = x² + y²

To determine the rate at which the distances are changing, we would differentiate with respect to t. It becomes

2zdz/dt = 2xdx/dt + 2ydy/dt- - - -- - -1

One travels south at 32 mi/h and the other travels east at 60 mi/h. It means that

dx/dt = 32

dy/dt = 60

Distance = speed × time

Since t = 0.5 hour, then

x = 32 × 0.5 = 16 miles

y = 60 × 0.5 = 30 miles

z² = 16² + 30² = 256 + 900

z = √1156

z = 34 miles

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2 × 34 × dz/dt = (2 × 16 × 32) + 2 × 30 × 60

68dz/dt = 1024 + 3600

68dz/dt = 4624

dz/dt = 4624/68

dz/dt = 68 mph

6 0
3 years ago
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