Answer:
Annual depreciation= $10,160 a year
Explanation:
Giving the following information:
Ivanhoe Company purchased a new machine on October 1, 2017, for $77,980. The company estimated that the machine has a salvage value of $6,860. The machine is expected to be used for 72,900 working hours during its 7-year life.
Annual depreciation= (original cost - salvage value)/estimated life (years)
Annual depreciation= (77,980 - 6,860)/7= $10,160 a year
The transaction for the bill for newspaper advertising services will be recorded today as a debit to Advertising Expenses and a credit to Accounts Payable (Advertising Payable).
<h3>How is an accrued expense recorded?</h3>
An accrued expense refers to an incurred outgoing that the service has been enjoyed previously and payment is due later.
According to the matching principle and accrual concept of generally accepted accounting principles, all expenses incurred within a financial period must be recognized in that period whether cash has been exchanged or not.
Thus, the transaction for the bill for newspaper advertising services will be recorded today as a debit to Advertising Expenses and a credit to Accounts Payable (Advertising Payable).
Learn more about recording accrued expenses at brainly.com/question/14524895
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Answer: 19.93 minutes
Explanation:
This is the complete question
Fast Auto Service provides oil and lube service for cars. It is known that the mean time taken for oil and lube service at this garage is 15 minutes per car and the standard deviation is 2.4 minutes. The management wants to promote the business by guaranteeing a maximum waiting time for its customers. If a customer's car is not serviced within that period, the customer will receive a 50% discount on the charges. The company wants to limit this discount to at most 2% of the customers. What should the maximum guaranteed waiting time be? Assume that the times taken for oil and lube service for all cars have a normal distribution
The solution is attached below
Answer:
a) H0: u = presence of a unit root
HA: u ≠ presence of a unit root ( i.e. stationary series )
b) t stat = -0.064
c) We will reject the Null hypothesis and the next step will be to accept the alternative hypothesis
d) It is not valid to compare the estimated t stat with the corresponding critical value because a random walk is non-stationary while the difference is stationary because it is white noise
Explanation:
<u>a) stating the null and alternative hypothesis</u>
H0: u = presence of a unit root
HA: u ≠ presence of a unit root ( i.e. stationary series )
<u>b) performing the test </u>
critical value = -2.88
T stat = coefficient / std error
= -0.02 / 0.31 = -0.064
c) From the test, the value of T stat > critical value we will reject the Null hypothesis hence the next step will be to accept the alternative hypothesis
d) It is not valid to compare the estimated t stat with the corresponding critical value because a random walk is non-stationary while the difference is stationary because it is white noise
False.... The amount of money taken out of a check for taxes depends on how much you're getting paid.